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3 years ago

Us the figure to solve ill mark brainliest

Mathematics

1 answer:

Mashutka [201]3 years ago

7 0

Answer:

QN = 43

Step-by-step explanation:

3x-5 = 2x+8+3

3x-5 = 2x+11

x-5 = 11

x = 16

MP = 3x-5

MP = 3(16)-5

MP = 48-5

MP = 43

MP and QN are ≅ so QN = 43

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A DVD player costs a store $185 to purchase from the manufacturer. They mark the price of the DVD player up by 20% for profit. H

stellarik [79]

Answer:

$222

Step-by-step explanation:

$185 x 1.2 = $222

5 0

3 years ago

Read 2 more answers

26. Define a relation ∼ ∼ on R 2 R2 by stating that ( a , b ) ∼ ( c , d ) (a,b)∼(c,d) if and only if a 2 + b 2 ≤ c 2 + d 2 . a2+

Tresset [83]

Answer:

~ is reflexive.

~ is asymmetric.

~ is transitive.

Step-by-step explanation:

~ is reflexive:

i.e., to prove $\forall (a, b) \in \mathbb{R}^2$ , $(a, b) R(a, b)$ .

That is, every element in the domain is related to itself.

The given relation is $\sim: (a,b) \sim (c, d) \iff a^2 + b^2 \leq c^2 + d^2$

Reflexive:

$(a, b) \sim (a, b)$ since $a^2 + b^2 = a^2 + b^2$

This is true for any pair of numbers in $\mathbb{R}^2$ . So, $\sim$ is reflexive.

Symmetry:

$\sim$ is symmetry iff whenever $(a, b) \sim (c, d)$ then $(c, d) \sim (a, b)$ .

Consider the following counter - example.

Let (a, b) = (2, 3) and (c, d) = (6, 3)

$a^2 + b^2 = 2^2 + 3^2 = 4 + 9 = 13$

$c^2 + d^2 = 6^2 + 3^2 = 36 + 9 = 42$

Hence, $(a, b) \sim (c, d)$ since $a^2 + b^2 \leq c^2 + d^2$

Note that $c^2 + d^2 \nleq a^2 + b^2$

Hence, the given relation is not symmetric.

Transitive:

$\sim$ is transitive iff whenever $(a, b) \sim (c, d) \hspace{2mm} \& \hspace{2mm} (c, d) \sim (e, f)$ then $(a, b) \sim (e, f)$

To prove transitivity let us assume $(a, b) \sim (c, d)$ and $(c, d) \sim (e, f)$ .

We have to show $(a, b) \sim (e, f)$

Since $(a, b) \sim (c, d)$ we have: $a^2 + b^2 \leq c^2 + d^2$

Since $(c, d) \sim (e, f)$ we have: $c^2 + d^2 \leq e^2 + f^2$

Combining both the inequalities we get:

$a^2 + b^2 \leq c^2 + d^2 \leq e^2 + f^2$

Therefore, we get: $a^2 + b^2 \leq e^2 + f^2$

Therefore, $\sim$ is transitive.

Hence, proved.

3 0

3 years ago

When solving the equation 1/4x= 6+1/3x, what is the value in front of the x after getting the variable to the left side of the e

mafiozo [28]

Answer:

-1/12

Step-by-step explanation:

3 0

3 years ago

What is 1 and 3/10 plus 3 and 1/3

Mamont248 [21]

Answer:

4 19/30

Step-by-step explanation:

1 3/10 + 3 1/3 = 139/30 or 4.63333...

Simplyfiy 139/30 to 4 19/30

3 0

4 years ago

A circle is placed in a square with a side length of 18 mm, as shown below. Find the area of the shaded region.

finlep [7]

Answer: the shaded region = 69.66mm^2

Explanation:
Assume shaded region is X
Then :
X + Area of circle = area of square
X = area of square - area of circle

Find area of square:
Side length = 18mm
Area = 18 x 18 = 324

Find area of circle:
Side length of a square = the diameter of the circle = 18mm
And r(radius) = d/2 = 18/2 = 9
Area = pi x 9^2 = 254.34

Now find X
X = 324 - 254.34 = 69.66

3 0

3 years ago