The angles below are supplementary. What is the value of X?

Mathematics

2 answers:

zubka84 [21]3 years ago

7 0

So you make your equation 4x+20+40=180.
Add like terms and get 4x+60=180.
Subtract 60 from both sides, get 4x=120.
Divide boths sides by 4, get your answer of x=30.
Hope this helps

makvit [3.9K]3 years ago

3 0

30. A straight line is 180
Take 40 = 140
Take 20 = 120
Divide by 4 = 30
4x+20+ 40 = 180
Rearrange to find x
X= 180-60 all divided by 4
X= 120/4
X= 30

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What is the value of x in the triangle? A. 21 B. 10 C. 7 D. 7√3

enyata [817]

A

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2 years ago

I need help on this question

kherson [118]

Answer:

Step-by-step explanation:

Just put x = 80 and y = 210 into the equation...

or put x = 40, y = 90.

210 - 90 = 3(80-40)

120 = 120√

210 + 90 = 3(80+40)

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3 years ago

On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre

Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

$P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}$

$P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514$

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

$P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}$