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Alex Ar [27]
3 years ago
7

Rose picked 18 tulips and 20 daffodils. She divided the flowers into groups so that the same number of tulips and daffodils were

in each bouquet. What is the greatest number of bouquets she could have made?
Mathematics
2 answers:
wlad13 [49]3 years ago
7 0

Answer:

That depends on how many flowers we keep in each bouquet.

If 1 tulip & 1 daffodil is kept in a bouquet , then the greatest no. of bouquets she'll make = 18

If 2 tulips & 2 daffodils is kept in a bouquet , then the greatest no. of bouquets she'll make = 9

If 3 tulips & 3 daffodils is kept in a bouquet , then the greatest no. of bouquets she'll make = 6

If 6 tulips & 6 daffodils is kept in a bouquet , then the greatest no. of bouquets she'll make = 3

If 18 tulips & 18 daffodils is kept in a bouquet , then the greatest no. of bouquets she'll make = 2

but somehow 2 daffodils will be left .

Naddika [18.5K]3 years ago
5 0

Answer:

The greatest number of bouquets Rose could have is 2. 9 of each flower in each bouquet.

Step-by-step explanation:

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Which polynomial expression represents the perimeter of the rectangle? (3a + 4) (2a - 1)​
Katen [24]

Answer:

10a + 6

Step-by-step explanation:

3a + 4 + 2a - 1

5a + 3

2( 5a + 3)

10a + 6

7 0
3 years ago
If Javier has a car with a mass of 250,000 kg and it is acted upon with a force of 300 Newtons. What is the acceleration?
natima [27]

Answer:

<u>The acceleration is 0.0012 meters/seconds²</u>

Step-by-step explanation:

1. Let's review the information given to answer the question correctly:

Mass = 250,000 kg

Force = 300 Newtons

2. What is the acceleration?

Based on Newton's Second Law of Motion, let's recall that:

Force = Mass * Acceleration

Acceleration = Force/Mass

Replacing with the real values, we have:

Acceleration = 300/250,0000

Acceleration = 0.0012 meters/seconds² (we can't express acceleration using Newtons/kilograms as the unit).

8 0
4 years ago
21+4(3^2-5)<br><br>PLEASE ANSWER FAST​
lana [24]

37

Step-by-step explanation:

21 + 16

HOPE THIS HELPS!

8 0
3 years ago
Read 2 more answers
Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.
sdas [7]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation is given below.

PV = nRT

The equation can be written as

\rm PV = \dfrac{m}{M} \ RT\\\\\\MPV = mRT

Where M is the molar mass, P is the pressure, V is the volume, R is the universal gas constant, T is the temperature, and m is the mass of the gas.

Then the molar mass of a 0.622-gram sample of gas has a volume of 2.4 L at 287 K and 0.850 atm.

V = 2.4 L = 0.0024

P = 0.85 atm = 86126.25 Pa

T = 287 K

m = 0.622

R = 8.314

Then we have

\begin{aligned} \rm M \times 86126.25 \times  0.0024&= 0.622 \times  8.314 \times 287\\\\\rm M &= 7.18 \end{aligned}

Then the molar mass of the gas is 7.18.

More about the ideal gas equation link is given below.

brainly.com/question/4147359

#SPJ1

6 0
2 years ago
HELP ME ASAPPPPPP !!!!!!! Picture attached
cricket20 [7]
The answer is 7 good luck

7 0
3 years ago
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