-86 = -6(-3p - 3) - 5p
Distribute the -6 into the parentheses:
-86 = (-6 * -3p) + (-6 * -3) - 5p
-86 = 18p + 18 - 5p
Simplify:
-86 = 13p + 18
Subtract both sides by 18:
-86 - 18 = 13p + 18 - 18
-104 = 13p
Divide both sides by 13:
= 
= 
<u>p = -8</u>
<u></u>
Good luck! If you have any questions, don't be afraid to ask :))
-T.B.
The independent variable is is the price per bag.
The answer is 14. Hope this helped
Refer to the image attached.
Given: 
and 
are congruent.
To Prove: 
ABC is an isosceles triangle.
Construction: Construct a perpendicular bisector from point B to Line segment AC.
Consider triangle ABD and BDC,
(given)
(By the definition of a perpendicular bisector)
(By the definition of a perpendicular bisector)
Therefore, 
by Angle Side Angle(ASA) Postulate.
Line segment AB is congruent to Line segment BC because corresponding parts of congruent triangles are congruent.(CPCTC)
Answer:
A) mPQ = 71º
B) mSR = 161º
C) mQRT = 199ª
D) mPSR = 270º
E) mPS = 109º
Step-by-step explanation:
We know that mST is 19º and QR is also 19º because they're opposite angles. We also know that angle PUR is 90º.
If we subtract 19º from 90º we get 71º for mPQ.
We also know that TR is a 180º angle. Using this if we take 19º from 180º we're left with 161º for mSR.
Using the 180º from angle TR, as well as the 19º from mQR we know that mQRT has to be 199º.
A circle is 360º and a right angle is 90º. That means that mPSR is 270º.
Knowing that TR is 180º and that PR is 90º, PTº must be supplementary making it also 90º. Adding the 19º from ST to the 90º from TP we know that PS is 109º
