The expression is equivalent to which integer? 2(-57 divided by 3) + 20^2

Suppose that you put 2 dimes, 2 nickels, and 1 penny into a bag. Then you choose one coin from the bag without looking, and reco

kicyunya [14]

Answer:

p(nickle) = 9/25 = 36/100=36%

Step-by-step explanation:

saw this from Skills practice

3 0

3 years ago

Please help –8 = c /9 c=

kramer

Hey there! I'm happy to help!

We want to get c all by itself on one side of the equation. Usually variables go on the left side, so let's flip the equation around.

c/9=-8

If we multiply c/9 by 9, the 9 will cancel out because if you divide by 9 and then multiply by 9 it just equals 1. We can do this to isolate the c, but whatever you do to one side of the equation, you have to do to the other. So, we multiply both sides by 9.

c/9×9=-8×9

c=-72

Have a wonderful day! :D

4 0

4 years ago

Read 2 more answers

Which is true about rigid transformations and circles?

aliina [53]

A circle shape is persevered regardless of any rigid transformation <span />

5 0

3 years ago

Read 2 more answers

Wha is the area of this

Korvikt [17]

Octagon, stop sign.

Eight isoscles triangles. It looks like we're told the side is 9.9 and the height to the side (also called the apothem) is 12.

So each isosceles triangle has area (1/2)(9.9)(12) and we have eight of them,

area = 8(1/2)(9.9)(12) = 475.2

Answer: 475.2

Usually we wouldn't be told 9.9 -- this is the baby version. We know each of those isoscles triangles has unique angle 360/8=45 degrees, so the apothem and half the side of the octagon are a right triangle with acute angle 22.5 degrees.

The area of the right triangle with long leg 12, short leg x,

tan 22.5 = x/12 or

x = 12 tan 22.5

Twice that is what we're told is 9.9; let's check:

2x = 24 tan 22.5 = 9.941125496954282

The area of the little right triangle is

(1/2) 12 × 12 tan 22.5

and there are 16 of these

16 (1/2) 12 × 12 tan 22.5 ≈ 477.174

6 0

3 years ago

At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca

saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

$p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064$

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that $P(A) = 0.3064$

Probability of testing positive while never using the drug.

11% of 75%. So

$P(A \cap B) = 0.11*0.75 = 0.0825$

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693$

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0

3 years ago

The expression is equivalent to which integer? 2(-57 divided by 3) + 20^2 - 5