In this problem, you are asked to find the area of the
trapezoid. The formula in finding the area of the trapezoid is:
A = [(a + b)/2] x h
Where a = base 1
b = base
2
h =
height
Substituting the given measurements to the formula:
A = [(1.7 m + 6.7 m) / 2] x 5 m
A = (8.4 m / 2) x 5 m
A = 4.2 m x 5 m
A = 21 m^2
Therefore, the area of the trapezoid is 21 square meters.
Answer:
step 2
and then also in step 3 compensating the error in step 2
Step-by-step explanation:
I think I just answered this for another post.
sin(a - b) = sin(a)cos(b) - cos(a)sin(b)
so, step 1 is correct :
sin(A - 3pi/2) = sin(A)cos(3pi/2) - cos(A)sin(3pi/2)
but step 2 suddenly and incorrectly switched that central "-" to a "+".
yes, sin(3pi/2) = -1, but that is still an explicit factor in step 2. so it was not used to flip the central operation from subtraction to addition, and therefore this change was a mistake.
then, in step 3, another error was made by just ignoring the "-" sign of "-1" and still keeping the central "+" operation. this error compensated for the error in step 2 bringing us back by pure chance to the right result.
I guess it s 30 irdk
hope tis helps :D
15% of 40 is 6
Hope this helps :D
Answer:
The volume of the new prism is three times the volume of the old prism
Step-by-step explanation:
To carry out this problem we have to invent 3 variables that represent length, width and height
w = width
h = height
l = length = 19cm
Now we have to do the equation that represents the calculation of the volume of the prism
v = w * h * l
v = w * h * 19
v = 19hw
assuming the length is tripled
v = w * h * 3l
v = w * h * 3 * 19
v = 57wh
To know the volume of the new prism with respect to the previous one, we simply divide the volume of the new prism by the previous one.
57hw / 19hw = 3
The volume of the new prism is three times the volume of the old prism
