Gravity simply does not allow that
Answer:
Step-by-step explanation:
A parallel line will have the same slope as the reference line. In this case, I don't see the "given line" as promised in the question. If it does appear, and it looks like y = 5x + 3, for example, the slope is 5 and the new line will have the same slope.
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<u>If this slope is correct</u>, we can start the equation for the parallel line that goes through point (-3,2) by starting with:</h3><h3 /><h3>y = 5x + b</h3><h3 /><h3>We need a value of b that forces the line to go through point (-3,2). We can do that by using the given point in the equation and solving for b:</h3><h3>y = 5x + b</h3><h3>2 = 5(-3) + b</h3><h3>b = 17</h3><h3 /><h3>The parallel line to y=5x+3 is</h3><h3>y = 5x + 17</h3><h3 /><h3>See attachment.</h3><h3 /><h3 /><h3 />
Answer:
No solutions
Step-by-step explanation:
Isolate the absolute value:
|x−1| + 5 = 2
Subtract 5 from both sides:
|x-1| = -3
Since an absolute value can never be equal to a negative number, there are no solutions.
Answer:
here
Step-by-step explanation:
https://www.rcboe.org/cms/lib/GA01903614/Centricity/Domain/1351/21.2%20permutations%20and%20probability.pdf
For the first one EF is 119 degrees now since that's made with two radii it makes a central angle so whatever that arc is the central angle will be the same. fro the second one since SRQ is 52 degrees you just take that and subtract it from 180 to get SQ. I'm not quite sure about the third one. the forth you are taking the measurement of the arc its connected to and dividing that by 2 so it would be 71 degrees. I'm pretty sure in right.