Area of circle = πr2 = π(23)^2
The midpoint of 85 and 90 is 87
The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}
Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original
If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap
Answer:
<h3>
f(x) = - 3(x + 8)² + 2</h3>
Step-by-step explanation:
f(x) = a(x - h)² + k - the vertex form of the quadratic function with vertex (h, k)
the<u> axis of symmetry</u> at<u> x = -8</u> means h = -8
the <u>maximum height of 2</u> means k = 2
So:
f(x) = a(x - (-8))² + 2
f(x) = a(x + 8)² + 2 - the vertex form of the quadratic function with vertex (-8, 2)
The parabola passing through the point (-7, -1) means that if x = -7 then f(x) = -1
so:
-1 = a(-7 + 8)² + 2
-1 -2 = a(1)² + 2 -2
-3 = a
Threfore:
The vertex form of the parabola which has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1) is:
<u>f(x) = -3(x + 8)² + 2</u>
