Answer:
10
Step-by-step explanation:
Seeing the 5 12 13 triple you get 1/2x=5 so
x=10
Answer:
54-28=26-32=6
Step-by-step explanation:
54-28=26
32-26=6
For this case, the first thing to do is to use the equation of the given line.
We have then:
f (x) = 0.76x + 42.39
We substitute the value of x = 15:
f (15) = 0.76 * (15) + 42.39
f (15) = 53.79
Then, subtracting with the original value we have:
53.79-52.04 = 1.75
Answer:
the residual for when x = 15 is:
1.75
Answer:
Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is
.
Step-by-step explanation:
We are given the following information in the question:
Sample size, n = 120
Sample mean = 10 mm
Standard Deviation = 0.24 mm
Formula:
![\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Cmu%20%5Cpm%20z_%7Bcritical%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![z_{critical}\text{ at}~\alpha_{0.05} = 1.96](https://tex.z-dn.net/?f=z_%7Bcritical%7D%5Ctext%7B%20at%7D~%5Calpha_%7B0.05%7D%20%3D%201.96)
![10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}](https://tex.z-dn.net/?f=10%20%5Cpm%201.96%5Cdisplaystyle%5Cfrac%7B0.24%7D%7B%5Csqrt%7B120%7D%7D)
Hence, the correct interpretation for the confidence interval is given by option a).
A 95% confidence interval for the mean diameter of the 120 bearings in the sample is
.
We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.