Answer:
The measure of the arc x is 130°
Step-by-step explanation:
we know that
The semi-inscribed angle is half that of the arc it comprises
so
65°=(1/2)[arc x]
solve for x
arc x=(2)(65°)=130°
Answer:
900
Step-by-step explanation:
(n-2)*180
5*180=900
Answer:
502 m²
Step-by-step explanation:
We require to find b before calculating the surface area.
The volume (V) of a cuboid is calculated as
V = lbh ( l is length, b is breadth and h is height )
Here V = 510, l = b, b = 10 and h = 3, thus
b × 10 × 3 = 510
30b = 510 ( divide both sides by 30 )
b = 17
--------------------------
The opposite faces of a cuboid are congruent, thus
top/bottom area = 2(17 × 10) = 2 × 170 = 340 m²
front/back area = 2(17 × 3) = 2 × 51 = 102 m²
sides area = 2(10 × 3) = 2 × 30 = 60 m²
Surface area = 340 + 102 + 60 = 502 m²
Answer:
C = (2, 6)
Step-by-step explanation:
The coordinates of point C can be found as the weighted average of the endpoint coordinates. The weights are the reverse of the relative segment lengths.
For AC : CB = 3 : 1, we have ...
C = (A +3B)/(1+3) = ((-1, 0) +3(3, 8))/4 = (-1+9, 0+24)/4
C = (2, 6)
Factoring f(x) would give a factor (x-1-2i), so you can divide f(x) by this, leaving (x-3)(x+4)(x-1+2i), so the other roots are:
x=3
x=-4
x=1-2i
