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zysi [14]
3 years ago
7

What is the cube number that equals 6

Mathematics
2 answers:
musickatia [10]3 years ago
7 0

Answer: 6 Cubed= 216

Step-by-step explanation:

Crazy boy [7]3 years ago
4 0

Answer:

6 Cubed

=

216

Step-by-step explanation:

6 Cubed

=

216

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Write 7/6 as a decimal. Round to the nearest thousandth if necessary
Lisa [10]
7/6 is 1.167 rounded to the nearest thousandth.
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Nataly_w [17]

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Two piecewise functions are shown below. What is the value of
gizmo_the_mogwai [7]

Step-by-step explanation:

I am not sure what your problem here is.

you understand the inequality signs ?

anyway, to get

6×f(-2) + 3×g(1)

we can calculate every part of the expression separately, and then combine all the results into one final result.

f(-2)

we look at the definition.

into what category is -2 falling ? the one with x<-2, or the one with x>=-2 ?

is -2 < -2 ? no.

is -2 >= -2 ? yes, because -2 = -2. therefore, it is also >= -2.

so, we have to use

1/3 x³

for x = -2 that is

1/3 × (-2)³ = 1/3 × -8 = -8/3

g(1)

again, we look at the definition.

into what category is 1 falling ? the one with x > 2 ? or the one with x <= 1 ?

is 1 > 2 ? no.

is 1 <= 1 ? yes, because 1=1. therefore it is also <= 1.

so we have to use

2×|x - 1| + 3

for x = 1 we get

2×0 + 3 = 3

6×f(-2) = 6 × -8/3 = 2× -8 = -16

3×g(1) = 3× 3 = 9

and so in total we get

6×f(-2) + 3×g(1) = -16 + 9 = -7

3 0
2 years ago
Find the volume. Round your answer to the nearest hundredth.
barxatty [35]

Answer:

c. 162.56 cm3

Step-by-step explanation:

This

volume = L × W × H

7.6 × 6.9 × 3.1 = 162.56 cm3

6 0
3 years ago
I am confused on how to do this? please help!
IceJOKER [234]
You would take random numbers preferable smaller ones such as -1,0,1,2
You would put those in the place of x
Then you would square the value of x. After that you subtract 4. Whatever you come out with is your y value. Then you put the x value on the x axis and from that point count up or down to the number you need on the y axis. Together that would be your point
6 0
3 years ago
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