1, O because if either shows present it's O.
Answer:
A. Oedema and ion imbalance
Explanation:
The proximal tubule is very important to the maintenance of homeostasis in the renal microenvironment. The alterations of the physiological functions will therefore distort the reabsorption of other ions. The blockage of sodium reabsorption into the channel will leads to an hypotonic internal environment. This will afterward leads to reduction of the reabsorption of water into the organ and increase the reabsorption of other ions into it. This will have clinical effect on the organism. Which is oedema of the extracellular surrounding of the tubules through accumulation of fluids and could lead to imbalance in neurological sense due to the imbalance in other ions.
Provided that there's no diagram, most molecules have particular areas on the molecules, called the "active area" that act as a lock to a particular substrate's molecular structure, providing the key.
An enzyme's active area is only able to be "unlocked" by a certain substrate's "key".
Answer:
Explanation:
the purple allele (C) is dominant to the pink allele (c).
The frequency of C represents p while that of c represent q. Using the formula p+q= 1
The proportion of pink flower is 153/1000 = 0.153. This is also the frequency of the genotype cc (q^2).
Thud to find q which is the frequency of the c allele,
q = √0.153
q = 0.3912
From the formula p +q = 1 we can find p p = 1 - 0.3912
p which is the frequency of the C allele
p = 0.6088.
B. the proportion of all purple flowering plants that are heterozygotes and homozygotes is 847 / 1000 = 0.847
