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3 years ago

What does AB congruent symbol CD mean? AB and CD here have lines over them How is it different than AB=CD?

Mathematics

1 answer:

masha68 [24]3 years ago

4 0

Answer:

Suppose that we have two line segments, AB and CD. We know that they have the same length.

I know that AB¯¯¯¯¯¯¯¯=CD¯¯¯¯¯¯¯¯ means AB is identical to CD (aka. They are the same lines), and also that AB¯¯¯¯¯¯¯¯≅CD¯¯¯¯¯¯¯¯ means that AB and CD have the same size, but what does AB=CD mean?

Step-by-step explanation:

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(100 POINTS) Can anyone solve this math equation for me? Thank you!

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Answer:

Can you show the math equation?

Step-by-step explanation:

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3 years ago

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Solve the system of linear equations by graphing x - 3y = 3 4x + 3y = - 3

Colt1911 [192]

Answer:

Assuming your equations are:

x-3y=3

4x+3y=-3

The answers are x = 0 and y = -1.

See the image for the graph.

If this solution helped you, consider upvoting it and giving a brainliest!

Step-by-step explanation:

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2 years ago

S=a1/1-r

valentinak56 [21]

Answer:

Step-by-step explanation:

This is an infinite geometric series. This has a sum of $\frac{a}{1-r}$

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

First term:

$3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3$

Second term:

$3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}$

Let's see the common ratio: $\frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}$

Thus we have a = 3 and r = 1/4. Plugging into the formula of the infinite sum, we get:

$s=\frac{a}{1-4}=\frac{3}{1-\frac{1}{4}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4$

So, the answer is 4

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3 years ago

Write an equation for the description. The difference between a number x and 19 is 27.

ra1l [238]

Answer

x-19=27

Step-by-step explanation:

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3 years ago

) 8(-5d - 4z) use z = 7 and d = 8 WHAT IS THE ANSWER

Nitella [24]

If my ans was helpful u can follow me

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