Answer: 2.093
Step-by-step explanation:
As per give , we have
Sample size : n= 20
Degree of freedom : df= n-1=19
Significance level : 
Since , the sample size is small (n<30) so we use t-test.
For confidence interval , we find two-tailed test value.
Using students's t-critical value table,
Critical t-value : 
Thus, the critical value for the 95% confidence interval = 2.093
4/16 in simplest form is 1/4 because 4 goes into 4 1 time and 4 goes into 16 4 times
Answer:
-21
Step-by-step explanation:
1-2+4-8+16-32
=-21
Answer:
Let x equal the ice thickness. An equality that represents a safe ice thickness for walkability is:
x ≥ 4 inches
(Plus the graph)
Step-by-step explanation:
Defining a variable just means you let any letter or symbol take the place of something. But you have to specifically say what is what in order for it to be clear.
So I defined "x" as the variable to represent the ice's thickness. And since we want an inequality for all the safe thicknesses, we could say that "x" must be greater than or equal to 4 inches thick in order to safely walk on it.
Lastly, you'd graph it with a solid point on 4 with the arrow going to the right.
Answer:

Step-by-step explanation:
The zeros of the polynomial function are given us as -5,-1,2
If the zeros of a polynomial function are α,β,ω, the polynomial function can be obtained using the expression below:
f(x) = (x - α)(x - β)(x - ω)
where α = -5, β = -1, and ω = 2

<em>NB: To arrive at the answer, expand the brackets and after expansion, collect like terms to obtain the final answer</em>