Find the equation for the given graph. Slope: y-intercept: Equation:

HELP PLSS I WILL GIVE BRAINIEST PLEASE!!!!

Alenkasestr [34]

Answer:

Step-by-step explanation:

term | Phrase

inequality | 63<8k

Expression | bc+1-(8d-4)

Equation | w^4=81

7 0

3 years ago

Read 2 more answers

What is the yield on a corporate bond with a $1000

White raven [17]

The yield on the corporate bond of a face value of $1000 is 7.77%.

What is the percentage discount?

The percentage discount is the discount given on a product as compared to the given discount on 100 rupees.

Given, the face value of the bond is $1000.

Discounted price of the bond is $900.

Therefore, the fixed interest on the bond for that period will be

= $1000 × 7/100 = $70.

Now, the yield on that corporate bond = 70 × 100/900 % = 7.77% .

Hence, the yield on the corporate bond of a face value of $1000 is 7.77%.

Learn more about percentage discount here:

brainly.com/question/26178186

#SPJ4

5 0

1 year ago

Write the equation of the line that passes through the points (6,2) (4,1)

Alisiya [41]

Answer: y=1/2x-1

Step-by-step explanation:

To find the equation of the line that passes through the points, we need to find out slope, m.

$m=\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

We plug our points into this formula to find slope.

$m=\frac{1-2}{4-6} =\frac{-1}{-2} =\frac{1}{2}$

Our slope is 1/2. To find our y-intercept, b, we would plug any point into the equation for slope-intercept form.

y=mx+b

y=1/2x+b

1=1/2(4)+b

1=2+b

b=-1

Now that we know b, our equation is y=1/2x-1.

6 0

3 years ago

Use Simpson's Rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. Compare y

DiKsa [7]

The area of the surface is given exactly by the integral,

$\displaystyle\pi\int_0^5\sqrt{1+(y'(x))^2}\,\mathrm dx$

We have

$y(x)=\dfrac15x^5\implies y'(x)=x^4$

so the area is

$\displaystyle\pi\int_0^5\sqrt{1+x^8}\,\mathrm dx$

We split up the domain of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [4, 9/2], [9/2, 5]

where the left and right endpoints for the $i$ -th subinterval are, respectively,

$\ell_i=\dfrac{5-0}{10}(i-1)=\dfrac{i-1}2$

$r_i=\dfrac{5-0}{10}i=\dfrac i2$

with midpoint

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

with $1\le i\le10$ .

Over each subinterval, we interpolate $f(x)=\sqrt{1+x^8}$ with the quadratic polynomial,

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

Then

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that the latter integral reduces significantly to

$\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)$

which is about 651.918, so that the area is approximately $651.918\pi\approx\boxed{2048}$ .

Compare this to actual value of the integral, which is closer to 1967.

4 0

3 years ago

What does the f(n - 1) represent?

leonid [27]

I'm assuming that you are talking about sequences <3

In the context of a recursive formula where we have "n-1" in sub-index of "a", you can think of "a" as the previous term in the sequence. In the context of an explicit formula like "-5+2(n-1)" "n-1" represents how many times we need to add 2 to the first term to get the nth term.

Dw if you don't understand, sequences and functions isn't an easy topic

3 0

3 years ago