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Dahasolnce [82]
2 years ago
12

Molly earns a rebate each month on her movie tickets and books. She earns $0.25 for each movie ticket and $2 for each book. Last

month Molly purchased 4 movie tickets
and earned $17.
Part A: Create an equation that will determine the number of books she purchased. (3 points)
Part B: Solve this equation justifying each step with an algebraic property of equality. (6 points)
Part C: How many books did Molly purchase last month? (1 point)
Mathematics
1 answer:
svetoff [14.1K]2 years ago
7 0

Answer:

Step-by-step explanation:

A

lets say   t is each ticket

and b is each book

0.25t + 2b = 17 that is for both

for just books

2b = 17

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An equilateral triangle with side length 7 cm is shown in the diagram, work out the area of the triangle.
ElenaW [278]
If a triangle has sides of 7 cm and it is an equilateral you can draw a line right down the middle to form two congruent triangles.

These smaller triangles have a hypotenuse of 7cm and a base of 3.5 cm (7/2)

To work out the height, use Pythagoras’ theorem.

a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the other two sides

7^2 - 3.5^2 = 36.75

Square root answer

= 6.06 cm

That’s the height of the triangle

Area of a triangle is base x height divided by 2

So 7 x 6.06 = 42.43…

/2

= 21.2 cm^2 to one d.p

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3 years ago
What is the vertex of the equation, y= -3x^2+2x-7?
Genrish500 [490]

A

Given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then

The x-coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = - 3x² + 2x - 7 is in standard form

with a = - 3, b = 2 and c = - 7, hence

x_{vertex} = - \frac{2}{-6} = \frac{1}{3}

Substitute this value into the equation for y-coordinate

y = - 3 (\frac{1}{3})² + 2 ( \frac{1}{3}) - 7

  = - \frac{1}{3} + \frac{2}{3} - \frac{21}{3} = - \frac{20}{3}

vertex = ( \frac{1}{3}, - \frac{20}{3}) → A



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One

The sum of two rational numbers is always rational. sqrt(9) + sqrt(25) = 3 + 5 which is rational. sqrt(16/100) = 4/10 = 2/5 is also rational. 3/28 is rational as well.

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