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3 years ago

Which of the following is Ohm's Law? OR=xR O1-V/R OVR/ OV-/R

Physics

1 answer:

kodGreya [7K]3 years ago

8 0

Answer:

I=V/R

Explanation:

Ohm's law gives the mathematical relationship between, current, voltage and the resistance of the circuit. Its mathematical form is given by :

V = IR ....(1)

V = voltage (in volts)

I = current (in Ampere)

R = resistance (in ohms)

Equation (1) can be rewritten as :

$I=\dfrac{V}{R}$

Hence, the correct relation is I=V/R.

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How long does it take to travel?<br> 120 miles at 40mph

lianna [129]

Answer:

it takes 3 hours to travel

Explanation:

120 ÷ 40 = 3

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2 years ago

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Which of these would be a good model to demonstrate the fact that the galaxies are moving apart as the universe is expanding?

Sergio [31]

Answer: Option A: The spots on the balloon move away as the balloon is inflated.

one of the scientific models describes the galaxies are moving apart as the universe is expanding. This expansion theory came from the observation of red-shifted spectrum from all the directions indicating that the galaxies are moving away. This can be understood from the inflated balloon. Initially spots can be marked using a colored pen on the balloon.On inflating the balloon, it would be noticed that the spots on the balloon move away. Actually the position of the spots won't change, but the distance between the spots would expand. This is a good model to explain the expanding universe. The galaxies are neither moving in any random direction nor moving forward. So, rest of the options are not good models to explain the theory.

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3 years ago

While riding a horse, the horse suddenly comes to an abrupt stop. You fly forward and

natali 33 [55]

Answer:

For every action there is an opposite reaction.

Explanation:

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3 years ago

Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of

sergij07 [2.7K]

Answer:

A) 50.0 g Al

Explanation:

We can calculate the temperature change of each substance by using the equation:

$\Delta T=\frac{Q}{mC_s}$

where

Q = 200.0 J is the heat provided to the substance

m is the mass of the substance

$C_s$ is the specific heat of the substance

Let's apply the formula for each substance:

A) m = 50.0 g, Cs = 0.903 J/g°C

$\Delta T=\frac{200}{(50)(0.903)}=4.4^{\circ}C$

B) m = 50.0 g, Cs = 0.385 J/g°C

$\Delta T=\frac{200}{(50)(0.385)}=10.4^{\circ}C$

C) m = 25.0 g, Cs = 0.79 J/g°C

$\Delta T=\frac{200}{(25)(0.79)}=10.1^{\circ}C$

D) m = 25.0 g, Cs = 0.128 J/g°C

$\Delta T=\frac{200}{(25)(0.128)}=62.5^{\circ}C$

E) m = 25.0 g, Cs = 0.235 J/g°C

$\Delta T=\frac{200}{(25)(0.235)}=34.0^{\circ}C$

As we can see, substance A) (Aluminium) is the one that undergoes the smallest temperature change.

7 0

3 years ago

Water, which we can treat as ideal and incompressible, flows at 12 m/s in a horizontal pipe with a pressure of 3.0 x 10^4 Pa. If

frez [133]

Answer:

p2 = 9.8×10^4 Pa

Explanation:

Total pressure is constant and PT = P = 1/2×ρ×v^2

So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2

from continuity we have ρ×A1×v1 = ρ×A2×v2

v2 = v1×A1/A2

and

r2 = 2×r1

then:

A2 = 4×A1

so,

v2 = (v1)/4

then:

p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2

p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)

= 9.75×10^4 Pa

= 9.8×10^4 Pa

Therefore, the pressure in the wider section is 9.8×10^4 Pa

5 0

3 years ago