Answer:
Concave Mirror is placed behind the car bulb
Answer:
39)
a) distance traveled = 1 mile
b) displacement = 0 mile
40) - 4 (m/s)
41-) distance traveled = 5 [m]
displacement = 3.6 [m]
Explanation:
The distance differs from the displacement, the distance traveled is equal to the sum of all displacements made by the particle or object.
Displacement is the difference between the initial point and the final point where the object or particle was stopped.
Then we can use the equation given:
The minus sign means the particle is slowing down.
For the 41) we can see the attached image.
In the graph we can see that the particle moves north 3 miles, so that the first distance is 3 miles, then moves 2 miles east being the second distance of 2 miles. Thus the sum of the distances is 3 + 2 = 5 miles.
Displacement is the difference between the endpoint and the initial point since the form of displacement is a straight line, we can use the formula of the straight line or the theorem of Pythagoras.
Answer:
The error in tapping is ±0.02828 ft.
Explanation:
Given that,
Distance = 200 ft
Standard deviation = ±0.04 ft
Length = 100 ft
We need to calculate the number of observation
Using formula of number of observation
Put the value into the formula
We need to calculate the error in tapping
Using formula of error
Put the value into the formula
Hence, The error in tapping is ±0.02828 ft.
Answer:
Force on the spring will be equal to 10 N
Explanation:
We have given mass of the block m = 0.2 kg
Compression of the spring x = 0.01 m
Spring constant
It is not given what we have to find but i think we have to find force here
We know that force on the spring is given by
So the force on the spring will be 10 N
Answer:
30.63 m
Explanation:
From the question given above, the following data were obtained:
Total time (T) spent by the ball in air = 5 s
Maximum height (h) =.?
Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:
Total time (T) spent by the ball in air = 5 s
Time (t) taken to reach the maximum height =.?
T = 2t
5 = 2t
Divide both side by 2
t = 5/2
t = 2.5 s
Thus, the time (t) taken to reach the maximum height is 2.5 s
Finally, we shall determine the maximum height reached by the ball as follow:
Time (t) taken to reach the maximum height = 2.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =.?
h = ½gt²
h = ½ × 9.8 × 2.5²
h = 4.9 × 6.25
h = 30.625 ≈ 30.63 m
Therefore, the maximum height reached by the cannon ball is 30.63 m