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3 years ago

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Which of these would be a good model to demonstrate the fact that the galaxies are moving apart as the universe is expanding?

1 answer:

Sergio [31]3 years ago

3 0

Answer: Option A: The spots on the balloon move away as the balloon is inflated.

one of the scientific models describes the galaxies are moving apart as the universe is expanding. This expansion theory came from the observation of red-shifted spectrum from all the directions indicating that the galaxies are moving away. This can be understood from the inflated balloon. Initially spots can be marked using a colored pen on the balloon.On inflating the balloon, it would be noticed that the spots on the balloon move away. Actually the position of the spots won't change, but the distance between the spots would expand. This is a good model to explain the expanding universe. The galaxies are neither moving in any random direction nor moving forward. So, rest of the options are not good models to explain the theory.

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Help please I will mark you the brainly!

Fudgin [204]

D)

Explanation:

Coz the position changes with time but the position change is not constant throughout time So, D) does not have constant velocity

3 0

3 years ago

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A 50g ball is released from rest 1.0 above the bottom of thetrack

ludmilkaskok [199]

Answer:

The maximum height of the ball is 2 m.

Explanation:

Given that,

Mass of ball = 50 g

Height = 1.0 m

Angle = 30°

The equation is

$y=\dfrac{1}{4}x^2$

We need to calculate the velocity

Using conservation of energy

$\Delta U_{i}+\Delta K_{i}=\Delta K_{f}+\Delta U_{f}$

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

$\Delta U_{i}=\Delta K_{f}$

Put the value into the formula

$mgh=\dfrac{1}{2}mv^2$

Put the value into the formula

$50\times10^{-3}\times9.8\times1.0=\dfrac{1}{2}\times50\times10^{-3}\times v^2$

$v^2=\dfrac{2\times50\times10^{-3}\times9.8\times1.0}{50\times10^{-3}}$

$v=\sqrt{19.6}$

$v=4.42\ m/s$

We need to calculate the maximum height of the ball

Using again conservation of energy

$\dfrac{1}{2}mv^2=mgh$

Here, h = y highest point

Put the value into the formula

$\dfrac{1}{2}\times50\times10^{-3}\times(4.42)^2=50\times10^{-3}\times9.8\times h$

$y=\dfrac{0.5\times(4.42)^2}{9.8}$

$y=0.996\ m$

Put the value of y in the given equation

$y=\dfrac{1}{4}x^2$

$x^2=4\times0.996$

$x=\sqrt{4\times0.996}$

$x=1.99\ m\ \approx 2 m$

Hence, The maximum height of the ball is 2 m.

4 0

3 years ago

Which one of the following is the pigment found in redheads?

coldgirl [10]

The pigment found in redheads in pheomelanin

4 0

3 years ago

5. A star begins a s a ball of gas and dust pulled together by

erastova [34]

Answer:

d. Gravity

Explanation:

In the beginning of their lives, stars are formed when clouds of dust and gas are pulled together by gravity.

Hope this helps!!

Please mark as Brainliest

4 0

3 years ago

Convert the speed of light, 3*10^8<br> meters/second (m/s), to miles/day<br> (mi/day).

Sati [7]

I believe that would be 1,080,000,000 Kilometers per hour- lmk if that helps

6 0

3 years ago

Read 2 more answers