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3 years ago

How many tbsp of honey is needed for 20 cups of flour?

Mathematics

1 answer:

mr_godi [17]3 years ago

5 0

Answer:

16 TBSP

Step-by-step explanation:

I did the math on a calculator thought I owed it to you, took me forever.

; ) plz mark brainliest.

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The fish population of a lake is decreasing each year. A study is conducted. But, unfortunately some data was lost. The research

Solnce55 [7]

Answer:

$F(t) = 18000(0.6666)^{t}$

Step-by-step explanation:

The fish population after t years can be modeled by the following equation:

$F(t) = F(0)(1-r)^{t}$

In which F(0) is the initial population and r is the constant rate of decay.

Year one the fish population was 18000

This means that $F(0) = 18000$

In year three the fish population was 8000 fish.

Two years later, so $F(2) = 8000$

$F(t) = F(0)(1-r)^{t}$

$8000 = 18000(1-r)^{2}$

$(1-r)^{2} = 0.4444$

$\sqrt{(1-r)^{2}} = \sqrt{0.4444}$

$1 - r = 0.6666$

$r = 0.3334$

$F(t) = 18000(0.6666)^{t}$

4 0

3 years ago

Which proportion can be used to find 65% of 90?

tia_tia [17]

Answer:

58.5

Step-by-step explanation:

0.65 decimal form

then times that by 90

then you got the answer 58.5

7 0

3 years ago

Degree 3 polynomial with zeros 4, 6, and -2.

hjlf

Answer:

Step-by-step explanation:

hello :

an Degree 3 polynomial with zeros 4, 6, and -2 is :

f(x) = (x-4)(x-6)(x+2)

all polynomial are : a (x-4)(x-6)(x+2) a ≠ 0

4 0

3 years ago

Links will get banned

goblinko [34]

Answer:

22 cm long

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4 0

3 years ago

The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand

Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

$P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})$

$P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})$

$P(X > 1560) = P(Z > \dfrac{110}{220})$

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean $\mu_x$ = np = 52 × 0.3085 = 16.042

The standard deviation = $\sqrt {n \time p (1-p)}$

The standard deviation = $\sqrt {52 \times 0.3085 (1-0.3085)}$

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

$Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})$

$Pr ( Y > 20) = P(Z >1 .338)$

From z tables

P(Y > 20) $\simeq$ 0.0903

7 0

3 years ago