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romanna [79]
3 years ago
10

I need to know if i have this correct

Physics
1 answer:
kherson [118]3 years ago
4 0

Answer:

YES! you do have the right answer

Explanation:

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The average diameter of one tennis ball in a package of three is 6.8 cm. Which of the following is the combined volume of all th
Crank

We want to find the combined volume of 3 tennis balls. We will get that the combined volume is 493.7 cm^3

First, remember that for a sphere of diameter D, the volume is:

V = \frac{4}{3}*3.14*(\frac{D}{2})^3

Where 3.14 is pi.

Here we know that the average diameter of a tennis ball is 6.8cm, then we can replace that in the above equation to find the volume (in average) of a single tennis ball:

V = \frac{4}{3}*3.14*(\frac{6.8cm}{2})^3 = 164.5 cm^3

Now, in 3 balls of tennis, the combined volume will be 3 times the above one, this is:

3*V = 3*164.5cm^3 = 493.7 cm^3

If you want to learn more about volumes, you can read:

brainly.com/question/10171109

4 0
2 years ago
Any help would be highly appreciated, preferably with steps too!
qwelly [4]

Answer:

Help with what:?

Explanation:

5 0
3 years ago
In a double slit experiment, 450 nm light passes through two slits producing an interference pattern where the first bright frin
musickatia [10]

Answer:

1.3 x 10⁻⁴ m

Explanation:

\lambda = wavelength of the light = 450 nm = 450 x 10⁻⁹ m

n = order of the bright fringe = 1

θ = angle = 0.2°

d = separation between the slits

For bright fringe, Using the equation

d Sinθ = n \lambda

Inserting the values

d Sin0.2° = (1) (450 x 10⁻⁹)

d (0.003491) = (450 x 10⁻⁹)

d = 1.3 x 10⁻⁴ m

6 0
3 years ago
If you are trying to loosen a stubborn screw from a piece of wood with a screwdriver and fail, should you find a screwdriver for
dmitriy555 [2]

A fatter handle. This allows you to provide more torque to the screw, which should eventually loosen it.

4 0
3 years ago
Read 2 more answers
1. After a rabbit population reaches the carrying capacity of its habitat, what will most likely happen to
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C) alternately increase and decrease
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