Acceleration can be defined as the rate of change in the velocity of an object. Option C is correct.
<h3>What is
Acceleration?</h3>
- It is defined as the rate of change in velocity.
- It can also be defined as the rate of change in position in a particular direction.
Where,
- acceleration
- change in velocity
- time
Therefore, acceleration can be defined as the rate of change in the velocity of an object.
Learn more about Velocity:
brainly.com/question/2239252
We don't know anything about the amount of distance it travels, but that's okay. The only equation we need here is
velocity(final) = velocity(initial) + acceleration * time
vf = vi + (a * t)
The ball is dropped from rest, so vi = 0 m/s.
We want it so that the ball hits the ground with a final velocity of 60 m/s, so vf = 60 m/s.
We are given the acceleration due to gravity, a = 9.8 m/s^2.
We are solving for the time, t = ?.
Now we just plug in the values.
vf = vi + (a * t)
60 m/s = 0 m/s + (9.8 m/s^2)*(t)
60 = 9.8t
60 / 9.8 = t
t = 6.122 s
Hopefully this is the right answer.
Since the current is inversely propotional to its resistance, when the voltage is doubled the current will be one-half
The net force performs a total amount of work equal to
(45 N) (0.80 m) = 36 J
on the bullet, and this is in turn is equal to the change in the bullet's kinetic energy by the work-energy theorem. So we have
W = ∆K = 1/2 mv²
since the bullet starts at rest, where m = its mass and v = its final velocity.
Solve for v :
36 J = 1/2 (0.0050 kg) v² ⇒ v = 120 m/s
