Answer:
The mechanical advantage of the system is 8
Explanation:
the mechanical advantage measures how much the system multiplies the input force to get the output.
In the given:
The input force (effort) is 20 Newton
The output force (load) is 160 Newton
This means that the mechanical advantage is:
mechanical advantage = load / effort = 160 / 20 = 8
Note that the mechanical advantage is unit-less (has no unit) since it is a ratio between two forces.
Hope this helps :)
Answer:b) atoms
Explanation:which are in turn made up of protons, neutrons and electrons
The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
<h3>What is magnetic force?</h3>
Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:

where
The magnitude of the charge 
The velocity of the charge 
The magnitude of the magnetic field 
The angle between the directions of v and B 
By substituting the values we will get:


Hence the magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
To know more about Magnetic force follow
brainly.com/question/14411049
Answer:
A car accelerates from rest, and travels 400 m in 3.5 seconds. If
the net force on the car is 12,000 N what is the mass of the car? bzgs dvd d dv dvdvd dhd dbvd
Explanation:
shd dhd bdvd dhdbduhdbdhdbbdceudd f
Answer:
The minimum value of width for first minima is λ
The minimum value of width for 50 minima is 50λ
The minimum value of width for 1000 minima is 1000λ
Explanation:
Given that,
Wavelength = λ
For D to be small,
We need to calculate the minimum width
Using formula of minimum width


Where, D = width of slit
= wavelength
Put the value into the formula

Here,
should be maximum.
So. maximum value of
is 1
Put the value into the formula


(b). If the minimum number is 50
Then, the width is


(c). If the minimum number is 1000
Then, the width is


Hence, The minimum value of width for first minima is λ
The minimum value of width for 50 minima is 50λ
The minimum value of width for 1000 minima is 1000λ