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Crank
3 years ago
7

A toy car attached to a rope is traveling around in a circle. It makes 4 laps in 12s.What is the angular velocity of the toy car

?
Physics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

2.09 rad/s

Explanation:

Given that,

A toy car makes 4 laps in 12 s.

We need to find the angular velocity of the toy car. We need to find the angular velocity of the toy car.

4 laps = 25.13 rad

So,

v=\dfrac{25.13\ rad}{12\ s}\\\\v=2.09\ rad/s

So, the angular velocity of the toy car is 2.09 rad/s.

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Set the radius to 2.0 m and the velocity to 1.0 m/s. Keeping the radius the same, record the magnitude of centripetal accelerati
jek_recluse [69]

Answer:

a=4\ m/s^2

Explanation:

Given that,

Radius, r = 2 m

Velocity, v = 1 m/s

We need to find the magnitude of the centripetal acceleration. The formula for the centripetal acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{1}\\\\=4\ m/s^2

So, the magnitude of centripetal acceleration is 4\ m/s^2.

5 0
3 years ago
Which of the following materials could have been found in the giant cloud that formed the solar system?
iren2701 [21]
Liquid and solid water were not in the giant gas cloudr
6 0
3 years ago
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A Carnot engine operates between temperature levels of 600 K and 300 K. It drives a Carnot refrigerator, which provides cooling
KATRIN_1 [288]

Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

      \frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}} ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

     \frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} ...... (2)

Now, equating both equations (1) and (2) as follows.

 Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} = Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}        

        \gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}

                    = \frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})

                    = \frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})

                    = 2.5

Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.

4 0
3 years ago
A hockey puck with a mass of 0.175 kg slides over the ice. The puck initially slides with a speed of 5.25 m/s, but it comes to a
Neko [114]

Answer:

1.70 J

Explanation:

The heat dissipated is the difference in the kinetic energies.

This is given by

E = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

v_i and v_f are the initial and final velocities.

With <em>m</em> = 0.175 kg,

E = \frac{1}{2}\times0.175(2.85^2 - 5.25^2) = -1.701\text{ J}

The negative sign appears because energy is lost.

7 0
3 years ago
Read the following and identify the main parts of the experiment.
slava [35]

The independent variable refers to the type of socks (synthetic socks), the dependent variable is the number of blisters and the control is the two weeks that she switches back to the cotton socks.

<h3>What is the dependent variable?</h3>

In an experiment, the dependent variable is those being tested and changes according to the independent variable.

The control group is the set of experimental conditions that is used to compare a given outcome in an experiment.

In conclusion, The independent variable refers to the type of socks (synthetic socks), the dependent variable is the number of blisters and the control is the two weeks that she switches back to the cotton socks.

Learn more about the dependent variable here:

brainly.com/question/25223322

#SPJ1

4 0
2 years ago
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