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Crank
3 years ago
7

A toy car attached to a rope is traveling around in a circle. It makes 4 laps in 12s.What is the angular velocity of the toy car

?
Physics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

2.09 rad/s

Explanation:

Given that,

A toy car makes 4 laps in 12 s.

We need to find the angular velocity of the toy car. We need to find the angular velocity of the toy car.

4 laps = 25.13 rad

So,

v=\dfrac{25.13\ rad}{12\ s}\\\\v=2.09\ rad/s

So, the angular velocity of the toy car is 2.09 rad/s.

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An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi
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Answer:

Explanation:

All the displacement will be converted into vector, considering east as x axis and north as y axis.

5.3 km north

D = 5.3 j

8.3 km at 50 degree north of east

D₁= 8.3 cos 50 i + 8.3 sin 50 j.

= 5.33 i + 6.36 j

Let D₂ be the displacement which when added to D₁ gives the required displacement D

D₁ + D₂ = D

5.33 i + 6.36 j + D₂ = 5.3 j

D₂ = 5.3 j - 5.33i - 6.36j

= - 5.33i - 1.06 j

magnitude of D₂

D₂²= 5.33² + 1.06²

D₂ = 5.43 km

Angle θ

Tanθ = 1.06 / 5.33

= 0.1988

θ =11.25 ° south of due west.

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3 years ago
A rollercoaster car has 2500 J of potential energy and 160 J of
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6 0
3 years ago
Determine the velocity of a car that travels 28km in 2.2 hours
OLga [1]

Answer:

<h2>velocity = 12.73 km/hr.</h2><h2 />

Explanation:

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              =<u> 28 km </u>

                  2.2 hr

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2 years ago
A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the
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Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength  is given by

           \lambda = \dfrac{2L}{n}

where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

            f = n\dfrac{v}{2L}

now, wavelength calculation

      n = 1

           \lambda_1 = \dfrac{2\times 2}{1}

                    λ₁ = 4 m

      n = 2

           \lambda_2 = \dfrac{2\times 2}{2}

                   λ₂ = 2 m

      n =3

           \lambda_3 = \dfrac{2\times 2}{3}

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now, frequency calculation

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            f_1 =1\times \dfrac{50}{2\times 2}

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      n = 2

            f = n\dfrac{v}{2L}

            f_2 =2\times \dfrac{50}{2\times 2}

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      n = 3

            f = n\dfrac{v}{2L}

            f_3 =3\times \dfrac{50}{2\times 2}

                    f₃ = 37.5 Hz

8 0
3 years ago
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