Given :
Initial velocity, u = 12.5 m/s.
Height of camera, h = 64.3 m.
Acceleration due to gravity, g = 9.8 m/s².
To Find :
How long does it take the camera to reach the ground.
Solution :
By equation of motion :
Putting all given values, we get :
t = 2.56 and t = −5.116.
Since, time cannot be negative.
t = 2.56 s.
Therefore, time taken is 2.56 s.
Hence, this is the required solution.
Answer:
The value is
Explanation:
From the question we are told that
The velocity which the rover is suppose to land with is
The mass of the rover and the parachute is
The drag coefficient is
The atmospheric density of Earth is
The acceleration due to gravity in Mars is
Generally the Mars atmosphere density is mathematically represented as
=>
=>
Generally the drag force on the rover and the parachute is mathematically represented as
=>
=>
Gnerally this drag force is mathematically represented as
Here A is the frontal area
So
=>
=>