It's False; an octagon has 8 vertices. When you remove the starting vertex and the two adjacent vertices we're left with 5 possible diagonals
Answer:
D 2+6x
Step-by-step explanation:
-2/3(-3-9x)
(-2/3×-3)+(-2/3×-9x)
6/3+18x/3 = 2 + 6x
Step-by-step explanation:
the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).
I think your teacher made a mistake, or you made one when typing the question in here.
there is no factor r that creates
15×r = 9
and
9×r = 5/27
it would mean that
15 × r² = 5/27
r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81
r = 1/9
but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9
and 9 × 1/9 = 9/9 = 1 is NOT 5/27
so, this can't be right.
on the other hand
15 × r = 9
r = 9/15 = 3/5
and then
9 × 3/5 = 27/5
so, either the sequence should have been
15, 5/3, 5/27
or (and I suspect this to be true)
15, 9, 27/5
under that assumption we have
s1 = 15
r = 3/5
sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)
s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =
= 3 × 19683/390625 = 59049/390625 =
= 0.15116544 ≈ 0.151
Answer:
Step-by-step explanation:
Given
![3y + 7 + 4y + 3 = [\ ]y + [\ ]](https://tex.z-dn.net/?f=3y%20%2B%207%20%2B%204y%20%2B%203%20%3D%20%5B%5C%20%5Dy%20%2B%20%5B%5C%20%5D)
Required
Simplify
We have:
Collect like terms
Evaluate like terms
The answer will be d i believe
