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Sav [38]
2 years ago
5

Which statement describes the graph?

Mathematics
1 answer:
iren [92.7K]2 years ago
7 0

Answer:

hmm maybe 1?

Step-by-step explanation:

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When 200 gallons of oil were removed from a tank, the volume of oil left in the tank was 3/7 of the tank's capacity. what was th
ki77a [65]

Answer:

Step-by-step explanation:

"When 200 gallons of oil were removed from a tank" algebraically looks like this:

V - 200.

"...the volume of oil left in the tank was 3/7 of the tank's capacity" algebraically looks like this:

3/7(V)

Therefore, the equation is

V - 200 = 3/7(V)

Begin by multiplying both sides by 7:

7(V - 200) = 3V and

7V - 1400 = 3V so

-1400 = -4V so

V = 350 gallons

That's if the volume of the oil in the tank was 3/7 of the tank's capacity.

For the other part of the problem, we set up the equation almost the same, except the 3/7 is a 1/2:

V - 200 = 1/2(V)

Multiplying both sides by 2 gives you

2(V - 200) = V and

2V - 400 = V so

-400 = -V so

V = 400

7 0
2 years ago
How do you factor 6x² +7x-3? Please show the steps!
Gnesinka [82]
6x^2+7x-3=\ \ \ \ | write\  7x\ as\ -2x+9x\\\\ 6x^2-2x+9x-3=0\\\\ 2x(3x-1)+3(3x-1)=0\\\\\boxed{(2x+3)(3x-1)}=0
4 0
3 years ago
In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th
MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

\frac{20!}{18!2!}=190

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0
3 years ago
#14 Please answer the question
Ivenika [448]

Answer:

D is the right answer

Step-by-step explanation:

8 0
2 years ago
Suppose the local Barons team wins every game they play with a probability of 0.75. What is the probability that the Barons woul
kondaur [170]

Answer:

The probability is 0.173

Step-by-step explanation:

The probability is of winning is 0.75 = 75/100 = 3/4

This means that the probability of losing is 0.25 = 25/100 = 1/4

So if they are two win 4 games, they will lose three

We can get this probability using the Bernoulli approximation of the binomial theorem

So here, we have

P(X = 4) = 7 C 4 * 0.75^4 * 0.25^3

= 0.173034667969

which is approximately 0.1730

6 0
2 years ago
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