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nika2105 [10]
4 years ago
11

Find an equation of the tangent line to the curve at the given point. y = x + tan(x) at (pi, pi)

Mathematics
1 answer:
S_A_V [24]4 years ago
8 0
<span>Differentiating :

y' = 1 + sec^2(x),
</span><span>
cosπ=−1</span><span>

plug in pi = -1 ,for x:

1 + sec^2(pi) = 1 +  (-1)^2 
                      = 2</span>
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Answer:

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The relation is a function.

Step-by-step explanation:

A <u>relation</u> is any set of ordered pairs, which can be thought of as (input, output).

A function is a <em>relation</em> in which no two ordered pairs have the same first component and different second components.

Remember that a function can only take on <u>one output for each input</u>. We cannot plug in a value and get out two values.

The Vertical Line Test allows us to know whether or not a graph is actually a function.  If a vertical line intersects the graph in all places <u><em>at exactly one point</em></u>, then the relation is a function.

I did the Vertical Line Test on your given graph. As you can see from the attached screenshot, each vertical line crosses the graph only once. Therefore, the given relation is a function.

The <u><em>domain</em></u> of the given relation is the set of x-values, while the <em><u>range</u></em> is the set of y-values. You'll have to list the ordered pairs in order to determine the domain and range of the given relation.

Relation:  {(-4, -1), (-2, 1), (1, -2), (2, 4), (4, -4)}.

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Please mark my answers as the Brainliest if you find my explanations helpful :)

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Step-by-step explanation:

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