The table of values shows the height of a car of a Ferris wheel as it travels in a circular motion.
1 answer:
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Answer:
x^4 -53x^2 +108x +160
Step-by-step explanation:
If <em>a</em> is a zero, then (<em>x-a</em>) is a factor. For the given zeros, the factors are ...
p(x) = (x +8)(x +1)(x -4)(x -5)
Multiplying these out gives the polynomial in standard form.
= (x^2 +9x +8)(x^2 -9x +20)
We note that these factors have a sum and difference with the same pair of values, x^2 and 9x. We can use the special form for the product of these to simplify our working out.
= (x^2 +9x)(x^2 -9x) +20(x^2 +9x) +8(x^2 -9x) +8(20)
= x^4 -81x^2 +20x^2 +180x +8x^2 -72x +160
p(x) = x^4 -53x^2 +108x +160
_____
The graph shows this polynomial has the required zeros.
The graph that best represent the relationship between time and cost is option A as it is a proportional graph
<h3>How to know the graph that represent the relationship between time and number of team?</h3>Each week 6 teams register to participate.
Therefore, for every week 6 team register to participate in the competition.
This simply implies as time increases , the number of participant in the competition also increase.
Therefore, the equation that can be use to represent this situation is as follows:
y = 6x
where
- y = number of team registered
- x = time in weeks.
Hence, the graph that best represent the relationship between time and cost is option A as it is a proportional graph. The registered team increases as the time in weeks increase.
learn more on graph relationship here: brainly.com/question/12812258
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the penalty he'll incurred into, since July 6 is after the deadline of April 15, is I = Prt
now "t" is in years, how many days after April 15 to July 6? well, 15 + 31 + 30 +6, to convert to years, divide by 365
<u>Answer-</u>
<em>The correct answer is</em>
<em>∠BDC and ∠AED are right angles</em>
<u>Solution-</u>
In the ΔCEA and ΔCDB,
As this common to both of the triangle.
If ∠BDC and ∠AED are right angles, then
Now as
∠BCD = ∠ACE and ∠BDC = ∠AED,
∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)
Then, ΔCEA ≈ ΔCDB
Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.