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Fudgin [204]
3 years ago
10

Working alone it takes jull 8.4 hours to pick forty bushels of apples. Maria can pick the same amount in 15 hours.If the worked

together how long would it take them
Mathematics
1 answer:
son4ous [18]3 years ago
8 0

Answer: 5.39 hours

Step-by-step explanation:

For Jill:

Number of hours used = 8.4 hours

Number of bushels of apples picked = 40

Number of bushels of apples picked per hour will be: = 40/8.4 = 4.7619

For Maria:

Number of hours used = 15 hours

Number of bushels of apples picked = 40

Number of bushels of apples picked per hour will be: = 40/15 = 2.6667

We then add the number of bushels of apples picked per hour for both of them together. This will be:

= 4.7619 + 2.6667

= 7.4286

If they worked together, the hours they'll take to pick 40 bushel of apples will be:

= 40/7.4286

= 5.39 hours

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A small deck of 5 cards consists of 3 red Jards and 2 green cards.
Simora [160]

Answer:

Approximately 0.19.

Step-by-step explanation:

The cards were drawn with replacement. Therefore, the probability of drawing a red card will be (3 / 5) at every one of the seven draws. The probability of not drawing a red card would be (1 - (3/5)) = (2/5).

One way to get three red cards out of the seven draws would be \verb!red!\; \verb!red!\; \verb!red!\; \verb!green!\; \verb!green!\; \verb!green!\; \verb!green!. That corresponds to a probability of (3/5)^3\, (2/5)^{7-3}.

However, there are many other ways to get three red cards during the seven draws. For example:

  • \verb!red!\; \verb!red!\; \verb!green!\; \verb!red!\; \verb!green!\; \verb!green!\; \verb!green!,
  • \verb!red!\; \verb!red!\; \verb!green!\; \verb!green!\; \verb!red!\; \verb!green!\; \verb!green!.
  • \cdots.
  • \verb!green!\; \verb!green!\; \verb!green!\; \verb!green!\; \verb!red!\; \verb!red!\; \verb!red!.

There are \displaystyle {\genfrac{(}{)}{0}{0}{7}{3}} = 35 such ways in total to choose three draws out of seven draws.

These ways are mutually-exclusive. Each of these ways has a probability of (3/5)^3\, (2/5)^{7-3}. The probability for getting a red card on exactly three out of the seven draws would be:

\displaystyle {\genfrac{(}{)}{0}{0}{7}{3}} \, (3/5)^3\, (1 - (3/5))^{7-3} \approx 0.19.

5 0
3 years ago
Two identical quarter circles are cut from a rectangle as shown
ArbitrLikvidat [17]

Answer:

The quarter circle Is connect the triangle

it is Cut.

Step-by-step explanation:

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5 0
3 years ago
Suppose we pick three people at random. For each of the 2.32 The following questions, ignore the special case where someone migh
Fantom [35]

Answer:

Step-by-step explanation:

Given that we pick up three people at random.

We can ignore the leap year so we assume there are 365 days in a year.

Probability for a person to be born on a specific data is equally likely and hence equal to

\frac{1}{365}

Each person out of three persons is independent of the other.

Hence for the second person to have the same birthday would have equal probability.

X = No of persons to have common birthday is binomial with n =3 and p = \frac{1}{365}

a) the probability that the first two people share a birthday

= (\frac{1}{365})^2\\= \frac{1}{133225}

b) the probability that at least two people share a birthday

= P(X\geq 2)\\=P(x=2)+P(x=3)\\= 3C2 (\frac{1}{365} )^2*\frac{364}{365}+(\frac{1}{365})^3

4 0
3 years ago
Which of the following is a solution to the equation x^2 - 7x +5?
Dahasolnce [82]
X^2-14+5 I’m not sure though
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Ms.Coreas is trying to grow some Yeast in her lab for a Bread experiment… She starts with only 1 yeast cell and needs at LEAST 4
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21 cells

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7 0
3 years ago
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