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LuckyWell [14K]
3 years ago
9

The height distribution of NBA players follows a normal distribution with a mean of 79 inches and standard deviation of 3.5 inch

es. What would be the sampling distribution of the mean height of a random sample of 16 NBA players?
Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

The probability will be "0.0111".

Step-by-step explanation:

The given values are:

Mean,

\mu = 79

Standard deviation,

\sigma = 3.5

Now,

⇒ \sigma\bar x = \frac{\sigma}{\sqrt n}

         =   \frac{3.5}{\sqrt 16}

         =0.875

⇒ P(\bar x > 81) = 1 - P(\bar x < 81)

So,

= 1 - P{\frac{(\bar x - \mu \bar x )}{ \sigma \bar x}  < \frac{(81 - 79) }{0.875} ]

= 1 - P(z < 2.2857)

= 0.0111

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Try this solution (note, this is not the shortest way):

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