So yeah if someone can help me with

Mathematics

1 answer:

Law Incorporation [45]3 years ago

6 0

Answer:

y = x - 5

Step-by-step explanation:

The equation of the line parallel to the line $ax + by + c_1 = 0$ is $ax + by + c_2 = 0$ .

That is, equations of parallel lines differ only by constant.

The given equation is $y = x + 4$

This is written as $x - y + 4 = 0$

Therefore, the equation of the line parallel to this line is given by $x - y + c = 0$

The value of c is determined using the point given.

Substituting the point (3,-2) we get:

$3 + 2 + c = 0$

$\implies c = -5$

Therefore, the equation of the line becomes y = x - 5.

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Why is it that when comparing a squares area with a rectangles area, with the SAME PERIMETER, that the square has a greater area

julsineya [31]

Answer:

When finding for the area of a square ,the lenght will be squared automatically leading to a greater value which is greater that of the rectangle which is length multipled by Width

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3 years ago

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jok3333 [9.3K]

Answer:

J'(-2,5)

K'(-7,5)

M'(-3.5,2)

L'(5.5,2)

Step-by-step explanation:

Please refer to the image attached to this answer.

Trapezoid JKLM is reflected over the x-axis, what do we notice about the ordered pairs of the original figure and the ordered pairs of its reflection over the x-axis is described below.

Point J , K L and M , when reflected over x axis , there distance from the y axis remains the same in second quadrant. the x coordinate becomes negative however the y coordinates remains the same.

The coordinates will be as shown in the image attached.