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andreev551 [17]
3 years ago
10

So yeah if someone can help me with

Mathematics
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:

y = x - 5

Step-by-step explanation:

The equation of the line parallel to the line $ ax + by + c_1 = 0$ is $ ax + by + c_2 = 0 $.

That is, equations of parallel lines differ only by constant.

The given equation is $ y = x + 4 $

This is written as $ x - y + 4 = 0 $

Therefore, the equation of the line parallel to this line is given by $ x - y + c = 0 $

The value of c is determined using the point given.

Substituting the point (3,-2) we get:

$ 3 + 2 + c = 0$

$ \implies c = -5 $

Therefore, the equation of the line becomes y = x - 5.

You might be interested in
The function h=-16t^2 +1700 gives you the height h, of an object in feet, at t seconds. How long will it take the object to hit
garik1379 [7]

Answer:

The object will hit the ground after 10.308 seconds.

Step-by-step explanation:

h(t) = -16t² + 1700

If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.

-16t² + 1700 = 0   Plug this into a calculator if you have one.

t = -10.308 and t = 10.308

Since time can't be negative, your answer will be the positive value, 10.308.


6 0
3 years ago
A 16 ounce box of cereal is priced at $3.68. Find the cost per ounce *
ZanzabumX [31]

Answer:

0.23$

Step-by-step explanation:

16 ounce box of cereal is priced at =3.68$

∴1 ounce box of cereal is priced at=(3.68/16)$

                                                         =0.23$

6 0
3 years ago
How many lines of symmetry does this figure have<br> A 1<br> B, 2<br> C. 3<br> D, 4
defon

Answer:

A.1

Step-by-step explanation:

Trapezoids only have one vertical line of symmetry

6 0
3 years ago
Read 2 more answers
Need help on this please this one is hard for me
pshichka [43]

9514 1404 393

Answer:

  y = -7x

Step-by-step explanation:

The line goes through the origin, so the y-intercept is b=0.

The line goes through the point (1, -7), so has a "rise" of -7 for a "run" of 1. The slope is ...

  m = rise/run = -7/1 = -7

Then the slope-intercept form equation is ...

  y = mx + b

  y = -7x

6 0
2 years ago
Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$
Anna [14]

Answer:

\large\boxed{1\dfrac{1}{3}\ u^2}

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

6 0
3 years ago
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