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vovangra [49]
3 years ago
6

I am confused about this equation; 5x+2y=6, 7x+8y=-2 Does anyone think they can help me out?

Mathematics
2 answers:
ra1l [238]3 years ago
6 0

Answer:

I cannot solve it step-by-step because like I'm helping other people cuz I'm busy with my homework so just I'm going to direct you the question you're supposed to solve simultaneous equation by any method example elimination method substitution method then you get the answer if you get stuck you can inform me

Olenka [21]3 years ago
4 0

Answer:

(2,-2)

Step-by-step explanation:

Using elimination

7x+8y=-2

-20x-8y=-24

-13x=-26

x=2

7(2)+8y=-2

14+8y=-2

8y=-16

y=-2

(2,-2)

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Slope of a line that passes through the points (-4,-7) and (-2,-19) in simplest form
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2 years ago
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sergij07 [2.7K]
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4 0
3 years ago
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user100 [1]

\huge \sf༆ Answer ༄

According to the question ;

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y \propto x

Now, let's add a constant of proportionality to replace proportionality sign with equal to :

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = kx

[ where, k is proportionality constant ]

plug the value of x and y from any ordered pair in the table , for example : \sf(\dfrac{1}{5} , 2)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2 = k \times  \dfrac{1}{5}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:k = 2 \times 5

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:k = 10

Therefore, value of proportionality constant (k) is

\overbrace{  \underbrace{\underline{ \boxed{ \sf 10 }}}}

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3 years ago
If x+1/x = 12, find the value of x^2+1/x^2​
viktelen [127]

\boxed{\sf (a+b)^2=a^2+b^2+2ab}

Now

\\ \sf\longmapsto x+\dfrac{1}{x}=12

\\ \sf\longmapsto \left(x+\dfrac{1}{x}\right)^2=12^2

\\ \sf\longmapsto x^2+2\times x\times \dfrac{1}{x}+\left(\dfrac{1}{x}\right)^2=144

\\ \sf\longmapsto x^2+\dfrac{1}{x^2}+2=144

\\ \sf\longmapsto x^2+\dfrac{1}{x^2}=144-2=142

4 0
3 years ago
Read 2 more answers
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