Answer:
a
Step-by-step explanation:
ကိနဩန္ကိကိကိဩနဩတိ္ကိနဩန္ကိကိကိဩနဩတပဃဂ
Hello
<span>an equation for the line in point-slope form and general form is :
y = ax+b a : </span>slope ; the <span>Passing through (x' ; y')
</span>y' = ax'+b
y-y' =a(x-x') and : x' =2 y' = - 1
calculate a :
let : y = ax+b .....(D)
....<span>3y-x=7</span>....(D') or y = (1/3)x+7/3
.(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 1/3
slop(D)×(1/3) = -1
slope (D) = -3
equation for the line : y-y' =a(x-x')
y+1 =(-3) (x-2)
Answer:
1,050
Step-by-step explanation:
Answer:
we know that
The volume of the prism is equal to
V=L*W*H
where
L is the length side of the base of the prism
W is the width side of the base of the prism
H is the height of the prism
In this problem we have
L=\frac{d-2}{3d-9}=\frac{d-2}{3(d-3)}
W=\frac{4}{d-4}
H=\frac{2d-6}{2d-4}=\frac{2(d-3)}{2(d-2)}=\frac{(d-3)}{(d-2)}
Substitute the values in the formula
V=\frac{d-2}{3(d-3)}*\frac{4}{d-4}*\frac{(d-3)}{(d-2)}=\frac{4}{3(d-4)}=\frac{4}{3d-12}
therefore
the answer is the option
4/3d-12
Step-by-step explanation: