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sergeinik [125]
2 years ago
6

Justin is making cookies, using a recipe in which the ratio

Mathematics
1 answer:
Nikolay [14]2 years ago
7 0

Answer:

Part A - he will need 2 cups of sugar  

Part B - 12 : 6 : 3

Step-by-step explanation:

Part A :

8 divided by 4 is 2

Part B :

Multiply all the numbers by 3

Hope this helped! :)

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In a department store, a $40 dress marked, "save 25%." what is the discount? what is the sales price of the dress?
Bogdan [553]

Answer:

Discount = $10

Sales Price = $30

Step-by-step explanation:

Discount

= 25% of marked price

= 25% x $40

= (25/100) x 40

= $10  

Sales price = Marked price - Discount = $40 - $10 = $30

8 0
2 years ago
Write 1 3/4 as a decimal and as a percent
scoray [572]

Answer:

Decimal: 1.75

Percentage: 175%

3 0
2 years ago
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5) Find the value of the term in the arithmetic sequence. (an = a1 + (n - 1)d) 11,
kvasek [131]

Answer:

139, I am sorry if I'm wrong

Step-by-step explanation:

a1=11; d=19-11=8

a17=11+(17-1)*8=11+128=139

6 0
3 years ago
Which side lengths cannot form a triangle?
sineoko [7]

Answer:

answer is option A

A, 4+12>6✓

12+6>4✓

4+6>12×

because sum of two sides lengths ina a triangle should greater than the other side's length

5 0
3 years ago
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The mass of a proton is approximately 1.67 x 10−24, and the mass of an electron is approximately 9.11 x 10−28. Find the approxim
nataly862011 [7]

Answer:

≈ 1833

Step-by-step explanation:

To find ratio of proton mass to electron mass, we have to divide.

The numbers are given in <em>scientific notation</em>.

Let a number be  a*10^b and another be  c*10^d, when we divide, we will follow the rule shown below:

\frac{a*10^b}{c*10^d}=(\frac{a}{c}*10^{b-d})

Now, we use the information given to find the ratio:

\frac{1.67*10^{-24}}{9.11*10^{-28}}\\=(\frac{1.67}{9.11}*10^{-24--28})\\=0.1833*10^4

This means we can find the number by taking 4 decimal places to the right, so that would becomes:

0.1833*10^4=1833

The approximate ratio is 1833 [mass of proton is around 1833 times heavier than mass of electron]

7 0
3 years ago
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