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zubka84 [21]
3 years ago
11

In the fig. AD = DC and AB = BC. Prove that triangle ABD = triangle CDB​

Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0

<u>Statement                        |   Reason</u>

AD = DC                           |   given

AB = CB                           |    given

BD = DB                           |   reflexive property

ABD = CDB                      |    side-side-side congruency theorem

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<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

3 ( x ) + 55 = 85

Answer To Solving Y:

Let's solve your equation step-by-step.

3x + 55 = 85

Step 1: Subtract 55 from both sides.

3x + 55 − 55 = 85 − 55

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Step 2: Divide both sides by 3.

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<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer To The Angle:

( 3 ) ( 10 ) + 55 = 85

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

2 ( y ) - 5 = 95

Answer:

Let's solve your equation step-by-step.

2y − 5 = 95

Step 1: Add 5 to both sides.

2y − 5 + 5 = 95 + 5

2y = 100

Step 2: Divide both sides by 2.

2y / 2 = 100 / 2

y = 50

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer To The Angle:

( 2 ) ( 50 ) − 5 = 95

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Please don't come at me if I am wrong.....:\

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