Answer:the horizontal displacement is 34.64 meters
The maximum height is 15 meters
Step-by-step explanation:
As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is
R = U^2Sin2#)/g
Where
U represents the initial velocity of the ball
g is acceleration due to gravity
# represents the angle above the horizontal.
From the information given
# = 30 degrees
U = 20 m/s
g = 10m/s^2
R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10
= 34.64 meters
To determine the maximum height of the ball, H,
H = (U^2Sin^2#)/2g
H = (20^2 × Sin^2 30)/2×10
H = (400 × 0.866^2)/20 = 15 meters
Answer:
C. C=9/5F+32
Step-by-step explanation:
divided by 5 then multiply by 9 then add 32
Answer:
Image attached
Step-by-step explanation:
The question asks to represent the position of two animals in a the cartesian coordinates plane. This is two perpendicular axis, the y-axis is the vertical one and the x-axis is the horizontal one. The animals are represented by dots, called a for the seagull and b for the shark.
Since the y-axis is the vertical axis and they ask to draw the points with a verical difference between them, we will draw the points in it.
Say the x-axis represents the sea surfice. The seagull would be over the sea, and the shark under the sea surfice (under x-axis).
This is the resulting drawing
Answer:
It would have to be (C) 50.27 because 25 is too short for a diameter of 8 seeing it would be 8x4 to get 32 in which 25 is not long enough for. So the answer is C.
Its algebra. The original equation is
To solve for a variable, we reverse the order of operations, beginning with addition/subtraction, and then multiplication/division. To remove a number from one side, we must do the opposite to the other side. In this case, to get rid of the -121 we must add 121 to the -164. This gives us -43. Then, to get the x by itself, we must multiply the other side by 3. -43*3=129
When we are doing the opposite of an operation to the other side, we are really reversing the operation and, to keep both sides equal, we must do whatever we have done to one side to the other side. So when we have -121, we add 121 as it equals 0, therefore it is gone. Since a equation must be balanced, we have to do what we did to the other side (adding 121).