You can do this using synthetic division, which is the easiest way. If x - 2 = 0, then x = 2. That 2 will go outside the "box" and the leading coefficients of the terms in the polynomial will go inside the "box". 2 (1 -3 -10 24). Bring down the first number, the 1. Multiply that 1 by the 2 to get 2. Put that 2 up under the -3 and add to get -1. Multiply that -1 by the 2 to get -2. Put that =-2 up under the -10 and add to get -12. Multiply that -12 by the 2 to get -24. Put the -24 up under the 24 and add to get 0. That means that x - 2 is a factor of the polynomial. What's left, the bolded numbers, are the coefficients of a new polynomial that is one degree less than the polynomial you started with. In other words, when we divide your polynomial by x-2, you get 
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In the fig. AD = DC and AB = BC. Prove that triangle ABD = triangle CDB
1 answer:
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The given equation is
We need to solve the equation for q.
<u>Value of q:</u>
The value of q can be determined by solving the equation for q.
Thus, subtracting both sides of the equation by r, we get;
Now, dividing both sides of the equation by b, we have;
Simplifying the terms, we get;
Therefore, the value of q is
Hence, Option B is the correct answer.