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AURORKA [14]
2 years ago
13

Help!! I need this ASAP

Mathematics
2 answers:
topjm [15]2 years ago
5 0

Answer:

x = 15

Step-by-step explanation:

The sum of 30 and 4x = 90, that is

4x + 30 = 90 ← equation to solve

Subtract 30 from both sides

4x = 60 ( divide both sides by 4 )

x = 15

Rzqust [24]2 years ago
3 0

Answer:

x=15

Step-by-step explanation:

Well, you have 2 numbers that sum up to 90 (the angle) so you can first minus the one you know, making your number from 90-30=60. Now all thats left is the 4x=60, which you can do 60/4=15 to get your answer that x=15.

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PLEASE HELP 40 POINTS PLSSSSSSSS
sineoko [7]

Answer:

Point C

Step-by-step explanation:

Trust me it is correct

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8 0
2 years ago
A box of colored pencils contains exactly 6 red pencils. The probability of choosing a red pencil from the box is 2/7. How many
ZanzabumX [31]

Answer:

B.21

Step-by-step explanation:

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4 0
3 years ago
What is the slope of a line that is perpendicular to the line x = –3? –3 0 1/3 undefined
Elena L [17]

Answer:

slope = 0

Step-by-step explanation:

The line with equation x = - 3 is a vertical line parallel to the y- axis

A perpendicular line is therefore a horizontal line parallel to the x- axis

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8 0
3 years ago
Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound
cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

p_1=X_1/n_1=188/244=0.77049

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

p_2=X_2/n_2=197/247=0.79757

The difference between proportions is (p1-p2)=-0.02708.

p_d=p_1-p_2=0.77049-0.79757=-0.02708

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0
3 years ago
Hi, what is the answer to 4 • 7 – 62 ÷ 3
xeze [42]

Answer:

22/3

Step-by-step explanation:

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8 0
3 years ago
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