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Svetllana [295]
3 years ago
15

The mountain climber descended 437.85 feet every hour. What is the change in the climber's elevation after 6 hours?

Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0
The answer should probably be 2627.1 feet

Hope this helps!
Ghella [55]3 years ago
3 0

Answer:

2627.16  lower down the mountain

Step-by-step explanation:

Every hour, the mountain climber <u>decends </u> 437.85 ft. Using Every to give you a clue as what operation to use, you do

437.85* 6

2627.16

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Suppose Paul kicks a soccer ball straight up into the air with an initial velocity of 96 feet per second. The function h(t)= -16
tangare [24]

Answer:

(d)

Step-by-step explanation:

Given

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Required

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The x intercepts are where the graph crosses x axis.

From the attached plot, they are:

x = (0,0) and x = (6,0)

These represent the start and end of the ball that is launched.

Hence, (d) is true

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Answer:

B

Step-by-step explanation:

This asks for data from multiple people, and it not just a yes or no question

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2 years ago
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What is X the two numbers are 46 and 71
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Scores on a statewide standardized test are normally distributed with a mean of 12.89 and a standard deviation of 1.95. Certific
Ulleksa [173]

Answer:

Marcus score is 13.7, the mean is 12.89, and the standard deviation is 1.95, so I’ll do ( 13.7 – 12.89)/ 1.95, Since Marcus' z-score is 0.415. The area to the left of the z-score is 65.9% so therefore Marcus did scored better than 65.9% of the students. So Marcus needs to score 98% better of all the other students in order for him to receive an actual certificate.

Step-by-step explanation:

4 0
3 years ago
Plz help me with this
AnnZ [28]

Answer:  \bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, B=\dfrac{6}{5}  →   P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}

Half of that period is: \dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}

Calculate the period for each of the options to find a match:

A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}

7 0
3 years ago
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