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velikii [3]
3 years ago
8

Which expression shows the simplified form of (8r^-5) -3 ?

Mathematics
2 answers:
Eddi Din [679]3 years ago
8 0

Answer:

\frac{r^{15}}{512}

Step-by-step explanation:

(8r^-5)^ -3

(8r^{-5})^{-3)

Apply exponential property

(ab^m) ^n = a^m b^mn

Multiply the outside exponent with the exponents insde

(8r^{-5})^{-3)= 8^{-3}r^{-5*-3}=8^{-3}r^{15}

Appy property a^-m = 1/a^m to make the exponent positive

8^{-3}r^{15}= \frac{r^{15}}{8^3} =\frac{r^{15}}{512}

maksim [4K]3 years ago
7 0
(8r^{-5})^{-3}=8^{-3}r^{-5(-3)}= \cfrac{r^{15}}{8^3}= \cfrac{r^{15}}{512}
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