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1 year ago

A sport jacket that cost the retailer$25 is marked up$10. Write as a fraction the mark up compared to the cost

Mathematics

1 answer:

snow_lady [41]1 year ago

7 0

Answer:

2/5

Step-by-step explanation:

markup / cost = 10 /25 = 2/5

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Using the ratio 3 dogs to 2 cats if you had 15 dogs how many cats would there be

Bumek [7]

Answer: 10 cats

Step-by-step explanation:

3/2

15/x

3*5=15

2*5=10

3/2=15/10

7 0

2 years ago

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The students of a school fill 5 buses for a field trip. Each class fills bus. How many classes are riding on the buses?

defon

Answer:

The answer is 5

Step-by-step explanation:

Because each bus is assigned 1 class and there is only five buses so there are 5 classes

4 0

2 years ago

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a A hole in the shape of a hemisphere is carved into each face of a cube. The holes are identical and centered at the centre of

morpeh [17]

Diameter of each hemispheral holes = the diameter of a full sphere = side length of cube = 2 units.

<h3>What is a Hemisphere?</h3>

A hemishpere is half of a sphere. Thus, two hemispheres makes one full sphere.

Given the image as shown below, since the identical hemispheral holes are centered at the center of each fce and they touch each other at only one point, it means that two hemisphere meet to make one full sphere.

Therefore, the diameter of a full sphere = side length of cube.

Thus, diameter of each hemispheral holes = the diameter of a full sphere = side length of cube = 2 units.

Learn more about hemisphere on:

brainly.com/question/9280450

5 0

2 years ago

WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"

Feliz [49]

Recall Euler's theorem: if $\gcd(a,n) = 1$ , then

$a^{\phi(n)} \equiv 1 \pmod n$

where $\phi$ is Euler's totient function.

We have $\gcd(9,32) = 1$ - in fact, $\gcd(9,32^k)=1$ for any $k\in\Bbb N$ since $9=3^2$ and $32=2^5$ share no common divisors - as well as $\phi(9) = 6$ .

Now,

$37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} = 32\cdot\left(32^{(\cdots)}\right)^6$