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Minchanka [31]
3 years ago
8

15-12=3÷n how do I get the answer do i dived 3÷n

Mathematics
2 answers:
postnew [5]3 years ago
7 0

Answer:

n=1

Step-by-step explanation:

no, look at the pic and you will understand

Marianna [84]3 years ago
5 0
15-12=3
So 3 divided by 3= 1
So 1 is your answer
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Please help with this
eimsori [14]

Answer:

this is hard

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2 years ago
Part A
lesya692 [45]
Each candy bar cost $5

work:
x = cost of candy bar

3+8(x)=43
-3. -3 < subtract 3 both sides
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4 0
3 years ago
Given: N is the midpoint of LQ,
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Read 2 more answers
Factor 64 - P.<br> (8 - x(8 - x)<br> (8 + x (8 - x)<br> (X + 8)(x-8)
muminat

Question:

Factor 64-x^2

(8 - x)(8 - x)

(8 + x) (8 - x)

(X + 8)(x-8)

Answer:

Option B: (8+x)(8-x) is the factor

Explanation:

Given that the expression is 64-x^2

We need to find the factor of the given expression.

Let us rewrite the expression as 8^2-x^{2}

Since the expression is of the form a^2-b^2, let us use the identity a^2-b^2=(a+b)(a-b)

where a = 8 and b = x

Substituting the values in the identity, then the expression can be written as

8^2-x^{2}=(8+x)(8-x)

Thus, the factor of the expression is (8+x)(8-x)

Hence, Option B is the correct answer.

4 0
3 years ago
what effect does doubling the radius of a cone have on the volume of the cone if the height remains the same
Butoxors [25]
V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2

so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)

it is 4 times the old one
4 0
3 years ago
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