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2 years ago

How many bananas are needed to make the third scale balance?

Mathematics

1 answer:

frozen [14]2 years ago

8 0

The number of bananas required to make the third scale balance is 3.

<h3>What is a scale?</h3>

A scale is a tool used for weighting objects. If the objects on each side weigh the same the scale is balanced. Based on this, let's determine the possible weight of each fruit to balance the last scale.

Scale 1 (10 bananas/ 2 pineapples)

It is known 10 bananas weigh as much as 2 apples, but to solve this problem let's assume 10 bananas weigh a total of 1000 grams.

10 banans = 1000 grams = each banana weighs 100 grams
2 pineapples = 1000 grams = each pineapple weighs 500 grams

Scale 2 ( 1 pineapple / 2 bananas, 1 apple)

Using the same imaginary weights let's find the weight of the apple.

1 pineapple = 500 grams
2 bananas = 200 grams
1 apple = 300 grams (500 - 200 = 300)

Scale 3 (1 apple /x )

We know 1 apple is equal to 300 grams and 1 banana is equal to 100 grams. Based on this, the number of bananas to balance the scale is 3.

Learn more about balance in: brainly.com/question/7181548

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Step-by-step explanation:

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3 years ago

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From experience, an airline knows that only 80% of the passengers booked for a certain flight actually show up. If 9 passengers

Olenka [21]

Answer: 0.74

Step-by-step explanation:

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Binomial probability formula to find the probability of getting success in x trial :-

$P(x)=^nC_xp^x(1-p)^{n-x}$

Then , the probability that more than 6 of them show up will be :-

$P(x>6)=P(7)+P(8)+P(9)\\\\=^9C_7(0.8)^7(0.2)^{2}+^9C_8(0.8)^8(0.2)^{1}+^9C_9(0.8)^9(0.2)^{0}\\\\=\dfrac{9!}{7!(9-7)!}(0.8)^7(0.2)^{2}+(9)(0.8)^8(0.2)+(1)(0.8)^9\approx0.3020+0.3020+0.1342=0.7382\approx0.74$

Hence, the probability that more than 6 of them show up = 0.74

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3 years ago