The lot costs 5000 dollars.
<u>Step-by-step explanation:</u>
The cost of a House and the lot = $40,000.
Let us assume the cost of lot as 'x'
Given that, The cost of the house is 7 times as much as the lot.
Therefore, The cost of the house= 7x
The cost of both the house and the lot= x + 7x
$40,000 = x + 7x
40,000 = 8x
x = 40,000/8
x = 5,000
The lot costs $5000.
Answer:
The answer is c
Step-by-step explanation:
Answer:
Step-by-step explanation:
First Question: 4x-y=3
Second Question: ax+10y=6
First Answer: y=3-4x
Step 1: Property of Inequality!
4x-y=3 = (4x-4x) - y=(3-4x)
Step 2: Solve!
4x-4x=0 which leaves us with y=3-4x
Second Answer: y=6/10
Step 1: Property of Inequality!
ax+10y=6 = (ax-ax) + 10y= (6-ax)
Step 2: Solve!
10y=6 which leaves us with y=6/10
The answer is 3x+5=7
Is x=4