The weight of the container after the wax hardens is 0.18 N.
<h3>What is the law of conservation of mass?</h3>
We know that according to the law of the conservation of mass, the mass of an object can neither be created nor destroyed but it can be changed from one form to the other.
Looking at this law, we know that the mass would not change even after the time that the wax must have hardened. The total mass of the wax would have to be a constant.
Total mass would now be;
Mass of the wax + mass of the container
= 3 g + 15 g
= 18 g
Weight = 18/1000 * 9.8 m/s^2
= 0.18 N
Learn more about mass:brainly.com/question/13383562
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Answer: Crystals differ in physical properties, i.e., in hardness, cleavage, optical properties, heat conductivity, and electrical conductivity.
These properties are important since they sometimes determine the use to which the crystals are put in industry.
hope this helps :)
(A) 14.8 g → 1.48 × 10^7 µg
The prefix µ means “× 10^(-6)”, so 1 µg = 1 × 10^(-6) g
The conversion factor (CF) = 1 µ g/1 × 10^(-6) g
∴ Mass = 14.8 g × [1 µg/1 × 10^(-6) g] = 1.48 × 10^7 µg
(B) 3.72 g → 3.72× 10^(-3) kg
The prefix k means “× 10^3”, so 1 kg = 1 × 10^3 g
CF = 1 kg/1 × 10^3 g
∴ Mass = 3.72 g × [1 kg/1 × 10^3 g] = 3.72× 10^(-3) kg
(C) 7.5 × 10^4 J → 75 kJ
CF = 1 kJ/1 × 10^3 J
∴ Energy = 7.5 × 10^4 J × [1 kJ/1 × 10^3 J] = 3.72× 10^(-3) kJ = 7.5 × 10^1 kJ
= 75 kJ
Answer:
C₇H₁₄O₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 1.152 g
Mass of CO₂ = 2.726 g
Mass of H₂O = 1.116 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:
For carbon (C):
Mass of CO₂ = 2.726 g
Molar mass of CO₂ = 12 + (2×16)
= 12 + 32
= 44 g/mol
Mass of C = 12/44 × 2.726
Mass of C = 0.743 g
For hydrogen (H):
Mass of H₂O = 1.116 g
Molar mass of H₂O = (2×1) + 16
= 2 + 16
= 18 g/mol
Mass of H = 2/18 × 1.116
Mass of H = 0.124 g
For oxygen (O):
Mass of compound = 1.152 g
Mass of C = 0.743 g
Mass of H = 0.124 g
Mass of O =?
Mass of O = (Mass of compound) – (Mass of C) + (Mass of H)
Mass of O = 1.152 – (0.743 + 0.124)
Mass of O = 1.152 – 0.867
Mass of O = 0.285 g
Finally, we shall determine the empirical formula for the compound as follow:
C = 0.743 g
H = 0.124 g
O = 0.285 g
Divide by their molar mass
C = 0.743 / 12 = 0.062
H = 0.124 / 1 = 0.124
O = 0.285 / 16 = 0.018
Divide by the smallest
C = 0.062 / 0.018 = 3.44
H = 0.124 / 0.018 = 7
O = 0.018 / 0.018 = 1
Multiply by 2 to express in whole number.
C = 3.44 × 2 = 7
H = 7 × 2 = 14
O = 1 × 2 = 2
Empirical formula => C₇H₁₄O₂