<u>Answer:</u>
The percent composition of this compound is 94%
<u>Explanation:</u>
The reaction can be formed as
Based on no. of iron reacted,
n = m/M
% composition of
= 
= 94%
Answer:
C = 107.97 mol/L
Explanation:
Given data:
Volume of solution = 1.38 mL (1.38 mL× 1 L /1000 mL = 0.00138 L)
Mass of ammonium sulfite = 17.36 g
Concentration of solution =?
Solution:
We will calculate the number of moles of ammonium sulfite.
Number of moles = mass/molar mass
Number of moles = 17.36 g / 116.15 g/mol
Number of moles = 0.149 mol
Concentration:
C = n/V
C = concentration
n = number of moles of solute
v = volume in L
C = 0.149 mol / 0.00138 L
C = 107.97 mol/L
Answer:
I think it might be elements and compounds! I may be wrong though.
Answer:
20 x (6.022 x 10^23) atoms in 20 moles of Calcium.
Explanation:
A mole contains 6.022 x 10^23 atoms, which is also known as Avogadro's number, and this number is same for each element. So, there are 20 x (6.022 x 10^23) atoms in 20 moles of Calcium.
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