If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?

1 answer:

lina2011 [118]3 years ago

3 0

First, write the chemical reaction and balance it:

NBr3 + NaOH ---> N2 + NaBr + HOBr

2 NBr3 + 3 NaOH ---> N2 + 3 NaBr + 3 HOBr

Then the theoretical proportion is 2 NBr3 : 3 NaOH

The reactants are in the proportion 40 NBr : 48 NaOH

From the theoretical proportion you can make [2 NBr3 / 3 NaOH] * 48 NaOH = 32 NaOH.

Given that you have more than 32 moles of NaOH, this is the excess reactant.

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Write electron configurations for Gallium, Ga (Z=31), and show the total valence electrons

ivann1987 [24]

Answer: The electronic configuration of gallium is written below and number of valence electrons is 3.

Explanation:

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

Valence electrons are defined as the electrons present in the outermost shell of an atom.

We are given:

An element Gallium having atomic number as 31.

Number of electrons = 31

Electronic configuration of Gallium is: $(Z=31):1s^22s^22p^63s^23p^64s^23d^{10}4p^1$