Answer:
c
Step-by-step explanation:
the perimeter of the sector
A. 4.25 hrs.....4 25/100 reduces to 4 1/4.......1/4(60) = 60/4 = 15 minutes
so 4.25 hrs = 4 hrs and 15 minutes
b. 8.5 hrs.....8 5/10 reduces to 8 1/2.....1/2(60) = 60/2 = 30 minutes
so 8.5 hrs = 8 hrs and 30 minutes
c. 6.2 hrs.....6 2/10 reduces to 6 1/5.....1/5(60) = 60/5 = 12 minutes
so 6.2 hrs = 6 hrs and 12 minutes
d. 10.8 hrs.....10 8/10 reduces to 10 4/5.....4/5(60) = 240/5 = 48 minutes
so 10.8 hrs = 10 hrs and 48 minutes
If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
Answer:
Find the 58th term of the arithmetic sequence
−20
Step-by-step explanation:
2 5/6 = 2.83
1 3/4 = 1.75
2.83*1.75= 4.9525
