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koban [17]
2 years ago
15

Question 21

Mathematics
1 answer:
horsena [70]2 years ago
7 0

Answer:

<em>A(x) = 6x² + 26x </em>

Step-by-step explanation:

A(x) = 4x ( x + 10 ) - 2x ( 8 ) + \frac{2x(x)}{2} + \frac{2x(x+2)}{2}

A(x) = 4x² + x² + x² + 40x - 16x + 2x

<em>A(x) = 6x² + 26x</em>

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liberstina [14]
-\dfrac{k}{5}=\dfrac{7}{10}\\&#10;-10k=35\\&#10;k=-3.5
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Are greater than 0 and located to the right of 0 on a number
jolli1 [7]

Answer:

1. 0

2. true

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3 years ago
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The width of a rectangle measures (2.5u+9.8)(2.5u+9.8) centimeters, and its length measures (1.5u+3.9)(1.5u+3.9) centimeters. Wh
icang [17]

Solution,

We have,

Width of rectangle, b = (2.5u+9.8) cm

Length of rectangle, l = (1.5u+3.9) cm

We need to find the expression for the perimeter of the rectangle. The formula for the perimeter of a rectangle is given by:

Perimeter = 2(l+b)

P = 2[(2.5u+9.8)+(1.5u+3.9)]

Collecting like terms

P = 2[(2.5u+1.5u)+(9.8+3.9)]

P=2(4u+13.7)

⇒ P = 8u+27.4

So, the expression for the perimeter of the rectangle is (8u+27.4) cm.

3 0
2 years ago
Given z1 = -3
trasher [3.6K]

Answer:

See explanation

Step-by-step explanation:

The given complex number are:

z_1=-3\sqrt{3}+3i

and

z_2=6\cos 150\degree+6i\sin 150\degree

When we rewrite z_1=-3\sqrt{3}+3i in complex form, we obtain;

z_1=r(\cos \theta+i\sin \theta)

where

r=\sqrt{(-3\sqrt{3})^2+3^2 }=\sqrt{36}=6

and

\theta=tan^{-1}(\frac{y}{x})

\implies \theta=tan^{-1}(\frac{-3\sqrt{3}}{3})=150\degree

Hence,

z_1=6(\cos 150\degree+i\sin 150\degree)

z_1=6\cos 150\degree+6i\sin 150\degree

Hence

z_1=z_2

8 0
3 years ago
Find all constants a such that the vectors (a, 4) and (2, 5) are parallel.
Nezavi [6.7K]

Answer:

\displaystyle a = \frac{8}{5}.

Step-by-step explanation:

Two vectors (x_1,\, y_1) and (x_2,\, y_2) are parallel to one another if and only if the ratio between their corresponding components are equal:

\displaystyle \frac{x_1}{x_2} = \frac{y_1}{y_2}.

Equivalently:

\displaystyle \frac{x_1}{y_1} = \frac{x_2}{y_2}.

For the two vectors in this equation to be parallel to one another:

\displaystyle \frac{a}{4} = \frac{2}{5}.

Solve for a:

\displaystyle a = \frac{8}{5}.

\displaystyle \frac{8}{5} would be the only valid value of a; no other value would satisfy the \displaystyle \frac{x_1}{y_1} = \frac{x_2}{y_2} equation.

4 0
3 years ago
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