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koban [17]
3 years ago
15

Question 21

Mathematics
1 answer:
horsena [70]3 years ago
7 0

Answer:

<em>A(x) = 6x² + 26x </em>

Step-by-step explanation:

A(x) = 4x ( x + 10 ) - 2x ( 8 ) + \frac{2x(x)}{2} + \frac{2x(x+2)}{2}

A(x) = 4x² + x² + x² + 40x - 16x + 2x

<em>A(x) = 6x² + 26x</em>

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I need help please ): !
ivanzaharov [21]

Answer:

BC=54, DE=27

Step-by-step explanation:

(7x-1)2=16x-10

x=4

7(4)-1=27

16(4)-10=54

7 0
3 years ago
The mean weight of nine apples is 7.5 ounces. Three of the apples have
podryga [215]

9514 1404 393

Answer:

  7.25 ounces

Step-by-step explanation:

The sum of weights is the mean weight times the number of apples.

  sum of 9 = 7.5×9 = 67.5 . . . ounces

  sum of 3 = 8×3 = 24 . . . ounces

Then the sum of the weights of the remaining 6 is ...

  67.5 -24 = 43.5 . . . ounces

The mean weight of those 6 is ...

  (total weight of 6)/6 = mean weight of 6

  (43.5 oz)/(6) = 7.25 oz

The mean weight of the other 6 is 7.25 oz.

_____

<em>Additional comment</em>

If some have an average weight that is greater than the mean of all, the remaining must have an average weight that is less than the mean of all.

6 0
3 years ago
What's the difference between an equilateral and isosceles triangle
Monica [59]
Equilateral is all angles are equal and isosceles has two equal sides
4 0
3 years ago
Read 2 more answers
Find each sum or difference<br> -4 1/3 + 2 5/9
Ira Lisetskai [31]

Answer:

-2 8/9

Step-by-step explanation:

-4 + 2 = -2

1/3 = 3/9

3/9 + 5/9 = 8/9

Hope this helped :)

6 0
3 years ago
Read 2 more answers
Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x^3 − 3x^2 − 9x + 4 (a) Find the interval on which
Eduardwww [97]

Answer:

(-∞, -1 )∪(3, ∞)

Step-by-step explanation:

Given function,

f(x) = x^3 - 3x^2 - 9x + 4

Differentiating with respect to x,

f'(x)=3x^2-6x-9

For increasing or decreasing,

f'(x) = 0

\implies 3x^2-6x-9=0

By quadratic formula,

x=\frac{-(-6)\pm \sqrt{(-6)^2-4\times 3\times -9}}{6}

=\frac{ 6\pm \sqrt{36+108}}{6}

=\frac{6\pm \sqrt{144}}{6}

\frac{6\pm 12}{6}

\implies x = 3\text{ or } x = -1

In interval (-∞, -1 ), f'(x) = positive,

⇒ f(x) is increasing on (-∞, -1 ),

In interval (-1, 3), f'(x) = negative,

⇒ f(x) is decreasing on (-1, 3),

In interval (3, ∞), f'(x) = positive,

⇒ f(x) is increasing on (3, ∞),

5 0
3 years ago
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