Answer:
£14889.30
Step-by-step explanation:
The cost of the car = £15500.
For the first year,
depreciation = £15500 x 1%
= £155
Its worth after the first year = £15500 - £155
= £15345
For the 2nd year,
depreciation = £15345 x 1%
= £153.45
Its worth after the second year = £15345 - £153.45
= £15191.55
For the 3rd year,
depreciation = £15191.55 x 1%
= £151.9155
Its worth after the third year = £15191.55 - £151.9155
= £15039.6345
For the 4th year,
depreciation = £15039.6345 x 1%
= £150.3963
Its worth after the fourth year = £15039.6345 - £150.3963
= £14889.2382
Thus, the worth of the car in 4 years would be £14889.30
68x87 i think?
sorry if that isnt right..
Answer:
c
Step-by-step explanation:
x²+y²+4x+6y=0
compare with x²+y²+2gx+2fy+c=0
centre is (-g,-f)=(-2,-3)
radius=√(g²+f²-c)=√((-2)²+(-3)²-0)=√13
The coordinate of point S from the giving coordinate point is (-8,4)
<h3>Midpoint of coordinates</h3>
The formula for calculating the midpoint of coordinate point is expressed as:
M(x,y) = {(x₁+x₂)/2, (y₁+y₂)/2}
Determine the measure of the coordinate S
-2 = 4+x₂/2
2(-2) = 4+x₂
x₂ = -4-4
x₂ = -8
Similarly
0 = -4+y₂/2
0(2) = -4+y₂
y₂ = 4
Hence the coordinate of point S from the giving coordinate point is (-8,4)
Learn more on midpoint here: brainly.com/question/5566419
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