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Yuki888 [10]
3 years ago
13

Fractions: three oil tankers together contain 37 5/7 litres of oil. If two tankers have 11 3/14 litres and 12 3/7 litres of oil.

Find the oil in the third tanker
Mathematics
1 answer:
ale4655 [162]3 years ago
4 0

Step-by-step explanation:

It is given that, three oil tankers together contain 37 5/7 litres of oil.

Total volume of oil is \dfrac{264}{7}\ L

If two tankers have 11 3/14 litres and 12 3/7 litres of oil.

Oil in first tanker is \dfrac{157}{14}\ L

Oil in second tanker is \dfrac{87}{7}\ L

Oil in first and second tanker is :

\dfrac{157}{14}\ L+\dfrac{87}{7}\ L=\dfrac{331}{14}\ L

Noo, oil in the third tanker = total volume - (Oil in first tanker + second tanker )

=\dfrac{264}{7}\ L-\dfrac{331}{14}\ L\\\\=\dfrac{197}{14}\ L

Hence, this is the required solution.

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Compass bearings use the four directions on a compass in order to find the direction of one object from another. An example is N20°E. True bearings use the number of degrees measured clockwise from north an object is. An Example is 120°T.

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3 0
2 years ago
Read 2 more answers
Tom is buying topsoil for the flower bed shown below. One bag of topsoil covers 151515 square meters. How many bags of topsoil d
exis [7]

Answer:

2 bags of topsoil.

Step-by-step explanation:

The attached figure shows a flower bed.

One bag of topsoil covers 15 square meters.

We need to find how many bags of topsoil does Tom need to cover his flower bed.

The area of the flower bed is :

A=\dfrac{1}{2}\times 12\times 5\\\\=30\ m^2  

Let he has to cover x bags of topsoil. So,

x = Area of flower bed/Area of 1 bag of top soil

x = 30/15

x = 2

Hence, he will need 2 bags of topsoil to cover his flower bed.

6 0
3 years ago
Evaluate the expression when a=7 and b=4<br><br> 36/b+a
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36/7+4
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3 years ago
What is (f-g)(x)?<br><br> f(x)=x^4-x^2+9<br> g(x)=x^3+3x^2+12
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X^4 - x^2 + 9 - (x^3 + 3x^2 + 12) =

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6 0
3 years ago
Pls help me!! I just need help on both of the following questions, a-d on each
Ymorist [56]
I'll do a and e on the first one to show you how to do it

Then See if you can do the rest

a. 6(-3)<span><span>
</span></span>
When your multiplying or dividing with negative numbers; If one of your numbers is negative like the one above, your answer will be negative

So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18

e. -20 ÷ 5

same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4

You do b, c, d, and f on the first question. Tell me what you get and we'll go from there

</span>Now for the second question <span>

</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)

</span>a. 4(-2 \frac{1}{3}) + 7 \frac{1}{6}
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator

</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>

but when you times a negative by a negative you get a positive


Now you try b and c; let me know what you get, and we'll go from there!

</span>

7 0
3 years ago
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