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2 years ago

Will give brainliest

Mathematics

2 answers:

Dmitry_Shevchenko [17]2 years ago

7 0

Answer:

your answer will be A, C, D, and E

Step-by-step explanation:

hope it helps

have a nice day ^_^

Verdich [7]2 years ago

4 0

Answer:

A,C,D,E

Step-by-step explanation:

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How do you know what 0 to place the decimal point at for scientific notation? Please explain in detail.

laiz [17]

To convert a decimal into scientific notation, move the decimal point until you get to the left of the first non-zero integer. The number of places the decimal point moves is the power of the exponent, because each movement represents a "power of 10".

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2 years ago

at wassamatta university, 55.7% of the student body are males. choose one student at random. what is the probability that the st

Nitella [24]

100% - 55.7%

= 100% - 55% - 0.70%

= 45% - 0.70%

= 44.30%

-----------

This means that the probability of selecting a female student at random is 44.3% as a percentage.

7 0

2 years ago

Read 2 more answers

3 a. It takes Adriana 20 minutes to walk 5 blocks to the library. Complete the table of equivalent ratios to show Adriana’s two

Dafna11 [192]

Answer:

It takes 4 minutes per block and she can walk 12.5 blocks in 45 minutes.

Step-by-step explanation:

20 / 5 = 4 minutes per block

20 + 20 + 5 = 45

5 + 5 + 2.5 = 12.5

Hope this helps, I did the test last year.

6 0

2 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$