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mylen [45]
3 years ago
13

Evaluate the product of 12 and 2 minus the quotient of 45 and 5

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
6 0
13

The product of 2 numbers is when you multiply them together. 12x2=24

The quotient of 2 numbers is when you divide them. 45/5=9

24-9=13
lawyer [7]3 years ago
5 0
Answer:
22 and 9 ?
I am unsure.

Step By Step Explanation:
12 x 2 = 24 - 2 = 22
45 ÷ 5 = 9
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Sophie [7]

Answer:

Step-by-step explanation:

Given that:

T(x,y) = \dfrac{100}{1+x^2+y^2}

This implies that the level curves of a function(f) of two variables relates with the curves with equation f(x,y) = c

here c is the constant.

c = \dfrac{100}{1+x^2+2y^2} \ \ \--- (1)

By cross multiply

c({1+x^2+2y^2}) = 100

1+x^2+2y^2 = \dfrac{100}{c}

x^2+2y^2 = \dfrac{100}{c} - 1 \ \  -- (2)

From (2); let assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.

Now,

\dfrac{(x)^2}{\dfrac{100}{c}-1 } + \dfrac{(y)^2}{\dfrac{50}{c}-\dfrac{1}{2} }=1

This is the equation for the  family of the eclipses centred at (0,0) is :

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a^2 = \dfrac{100}{c} -1  \ \ and \ \ b^2 = \dfrac{50}{c}- \dfrac{1}{2}

Therefore; the level of the curves are all the eclipses with the major axis:

a =  \sqrt{\dfrac{100 }{c}-1}  and a minor axis b =  \sqrt{\dfrac{50 }{c}-\dfrac{1}{2}}  which satisfies the values for which 0< c < 100.

The sketch of the level curves can be see in the attached image below.

7 0
3 years ago
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maria [59]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Virty [35]

Answer:

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Step-by-step explanation:

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V2 be the speed of the other car

t1 the time it took for the first car to arrive

t2 the time it took for the second car to arrive

d1 the distance traveled by first car

d2 the distance traveled by second car

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Answer:

Step-by-step explanation:

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