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Fantom [35]
3 years ago
13

Find the missing value using the given information (4,p), (p,-3), m=5/3 Please help!

Mathematics
1 answer:
Margarita [4]3 years ago
4 0

Answer:

(4,2), (1,-3), m=5/3

Step-by-step explanation:

I kinda just used trial and error I guess. Since you find the slope by doing y-y1/x-x1. I did P--3 over 4-p =5/3 and just used logic to see which numbers fit

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Prove that x=2 if 4^x=8x...where ^ stands for "to the power of".
Romashka [77]
In order to prove this, you simply plug in the number 2 everywhere you see X:

4^(2) = 8(2). 

Simplify

16 = 16 √

Since this checks out, x is proven to be 2.
4 0
3 years ago
What is the solution to this system of linear equations?<br><br> x + y = 4<br><br> x − y = 6
Amiraneli [1.4K]
X+y = 4, therefore y = 4-x when you rearrange the equation.
You can subsitute this in: x-(4-x) = 6
-4+x = 6-x
x=10-x
2x = 10
x = 5
Substitute x into the previous equation:
5+y = 4
y = 4-5
y = -1
5 0
4 years ago
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I will mark brainlyest plss helpp
lana [24]

Answer:

The answer is C

Step-by-step explanation:

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5 0
3 years ago
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Sums of a sequence: How many total gifts did my true love give to me during the entire 12 days of Christmas? Hint: Without any o
ale4655 [162]
<span> On the first day of Christmas,
my true love sent to me
A partridge in a pear tree. On the second day of Christmas,
my true love sent to me
Two turtle doves,
And a partridge in a pear tree. On the third day of Christmas,
my true love sent to me
Three French hens,
Two turtle doves,
And a partridge in a pear tree. </span>

The song continues, adding 4 calling birds on the 4th day, 5 golden rings on the 5th, and so on up to the 12th day, when 12 drummers add to the cacophony of assorted birds, pipers and lords leaping all over the place.

Notice that on each day there is one partridge (so I will have 12 partridges by the 12th day), and each day from the second day onwards there are 2 doves (so I will have 22 doves), and from the 3rd there are 3 hens (total of 30 hens), and so on.

So, how many presents are there altogether?

Partridges: 1 × 12 = 12

Doves: 2 × 11 = 22

Hens 3 × 10 = 30

Calling birds: 4 × 9 = 36

Golden rings: 5 × 8 = 40

Geese: 6 × 7 = 42

Swans: 7 × 6 = 42

Maids: 8 × 5 = 40

Ladies: 9 × 4 = 36

Lords: 10 × 3 = 30

Pipers: 11 × 2 = 22

Drummers: 12 × 1 = 12

Total = 364

We observe that we have the same number of partridges as drummers (12 of each); doves and pipers (22 of each); hens and lords (30 of each) and so on. So the easiest way to count our presents is to add up to the middle of the list and then double the result: (12 + 22 + 30 + 36 + 40 + 42) × 2 = 364.


3 0
3 years ago
Read 2 more answers
Solve the system of linear equations by substitution
Bond [772]

Answer:

(-4, 5)

Step-by-step explanation (work shown in attached picture):

1) Since x is already isolated in the first equation, substitute that value for x into the other equation to find y. So, substitute 16-4y for the x in 3x + 4y = 8, then solve for y. This gives us y = 5.

2) Now, substitute that given value for y back into any one of the equations to find x. I chose to do it in the first equation. Substitute 5 for the y in x = 16-4y, then solve for x this time. This gives us x = -4.

Since x = -4 and y = 5, the solution is (-4, 5).  

5 0
3 years ago
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