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ElenaW [278]
3 years ago
10

The answer is b, you could have just said that...

Mathematics
1 answer:
vesna_86 [32]3 years ago
8 0

um what is this.

im confused.

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SOMEONE PLS HELP QUICK WILL GIVE BRAiNLIEST
skad [1K]

Answer:

1. x^2-9x+18

2. 2x^2-4x-16

3. 3x^2-19x-14

4. 6x^2 +14x + 8

Step-by-step explanation:

1. (x-3)(x-6)

x^2 - 6x - 3x +18 = x^2-9x+18

2. (2x+4)(x-4)

2x^2-8x+4x-16 = 2x^2-4x-16

3. (x-7)(3x+2)

3x^2+2x-21x-14 = 3x^2-19x-14

4. (3x+4)(2x+2)

6x^2+6x+8x+8 = 6x^2 +14x + 8

6 0
3 years ago
How do you calculate angles on a straight line??
dimaraw [331]

Answer:

Step-by-step explanation:

Straight line is an angle whose vertex point(O) has a value of 180. The arms (OA & OB) of the straight line angle lies opposite to each other from the vertex point

Sum of all the angles in a straight line  = 180

From this you can find the value of unknown angle, if other angles are given.

∠AOC + ∠BOC = 180

3 0
2 years ago
Read 2 more answers
at what rate of interest the compound amount on rs 8000 for 2 years is rs 10648? Please someones help me ​
alexandr402 [8]

Answer:

hope this helps and pls mark as brainliest

8 0
3 years ago
Find the x-coordinate of the point on the graph of y=x^2 where the tangent line is parallel to the secant line that cuts the cur
jek_recluse [69]
First find the secant line. The slope of the secant line through (-1,1) (when x=-1) and (2,4) (when x=2) is the average rate of change of y=x^2 over the interval [-1,2]:

\text{slope}_{\text{secant}}=\dfrac{2^2-(-1)^2}{2-(-1)}=\dfrac33=1

The tangent line to y=x^2 will have a slope determined by the derivative:

y=x^2\implies y'=2x

Both the secant and tangent will have the same slope when 2x=1, or when x=\dfrac12.
4 0
3 years ago
Plz help i dont understand this
OLEGan [10]
I think it’s 27

explanation:
5 0
3 years ago
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